Let first number is x
second number be y
one number is four less than a second number: x=y-4
Three times the first is 6 more than 6 times the second: 3x=6y+6
substitute x=y-4 in 3x=6y+6
3x =6y+6
3(y-4)=6y+6
3y-12=6y+6
3y-6y=6+12
-3y=18
y=-6
substitute y=-6 in x=y-4
x=-6-4=-10
so first number is -10
second number is -6
Mean=5
sd=2
Using Z(x)=(x-mean)/sd
Z(2)=(2-5)/2=-1.5
Z(6)=(6-5)/2=0.5
Therefore
probability of finding a spot between 2 and 6 minutes is
P(x<6)-P(x<2)
=P(Z<0.5)-P(Z<-1.5)
=0.6915-0.0668
=0.6247
=>
More than half of the students (62.5%) finds a space between 2 and 6 minutes.
Answer:
.........................a.......................
The gcm is 30 and the lcm is 5
Answer: All four runners ran .96 seconds
Step-by-step explanation: The total time of the four runners, divided by the amount of runners.
3.86/4= .965