$(q\mathrm{}p)(x)$ $\begin{gathered} q(p(x))=q(-2x+1) \\ =-(-2x+1)^2 \\ So\text{ } \\ (q\mathrm{}p)(5)=-(-2\times5+1)^2 \\ =-(9)^2 \\ =-81 \end{gathered}$

Now let;s solve the second part

$\begin{gathered} (p\mathrm{}q)(x)=p(q(x)) \\ =p(-x^2) \\ =-2(-x^2)+1 \\ =2x^2+1 \\ So\text{ (p.q)(5) will be } \\ (p\mathrm{}q)(5)=2(5)^2+1 \\ =51 \end{gathered}$

6 0

1 year ago

4. Sammy created a model of a frontier fort. He used a scale

alina1380 [7]

Answer:

18 ft. tall

Step-by-step explanation:

This is because if 1 in. equals 2 ft. and the wall of the model were 9 ft. tall you would multiply 9 in. by 2 ft. and get 18 ft.

3 0

3 years ago