// Simple Java program to find sum of series
// with cubes of first n natural numbers
import java.util.*;
import java.lang.*;
class GFG {
/* Returns the sum of series */
public static int sumOfSeries(int n)
{
int sum = 0;
for (int x = 1; x <= n; x++)
sum += x * x * x;
return sum;
}
// Driver Function
public static void main(String[] args)
{
int n = 5;
System.out.println(sumOfSeries(n));
}
}
// Code Contributed by Mohit Gupta_OMG <(0_o)>
Answer:
ip = enrollment + section;
Explanation:
The variable ip has been declared to be a pointer to int.
int * ip;
The variable enrollment has been declared as an array of 20 elements .
int enrollment[20];
The variable section has been declared as an int.
int section;
In order to make ip point to the element in the array indexed by section, we can use the following statement :
ip = enrollment + section;
This will make ip point to enrollment[section].
Explanation:
10:A program that assigns the sum 20,30,40
20: input 20,30,40
30:sum input
40: print total
End
