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2 years ago

Multiply. Type your answer in the box. Do not use any spaces. (+19) x (–3) =

Mathematics

2 answers:

Rama09 [41]2 years ago

7 0

Answer:

-57

Step-by-step explanation:

(19)(-3) multiply nineteen and negative three

shtirl [24]2 years ago

5 0

Answer:

-57

Step-by-step explanation:

19(-3)=-57

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2 years ago

Consider the vector add = a + b = [13 12 11 10 10] and sub = a - b = [-11 - 6 - 14 8]. Find the vector a and b.

prisoha [69]

Answer:

a = [1 3 5 7 9] and b = [12 9 6 3 1]

Step-by-step explanation:

The addition of two vectors a and b is defined as

a + b = [13 12 11 10 10] .... (1)

The subtraction of two vectors a and b is defined as

a - b = [-11 - 6 - 1 4 8] .... (2)

After adding (1) and (2), we get

(a + b) + (a - b)= [13 12 11 10 10] + [-11 - 6 - 1 4 8]

On simplification we get

2a = [13-11 12-6 11-1 10+4 10+8]

2a = [2 6 10 14 18]

Divide both sides by 2.

a = [1 3 5 7 9]

Substitute the value of vector a in equation (1).

[1 3 5 7 9] + b = [13 12 11 10 10]

Subtract vector a from both sides.

b = [13 12 11 10 10] - [1 3 5 7 9]

On simplification we get

b = [13-1 12-3 11-5 10-7 10-9]

b = [12 9 6 3 1]

Therefore the vectors a and b are defined as a = [1 3 5 7 9] and b = [12 9 6 3 1].

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2 years ago

How many five-card hands (drawn from a standard deck) contain exactly three fives? (A five-card hand is any set of five differen

VashaNatasha [74]

Answer:

4512.

Step-by-step explanation:

We are asked to find the number of five-card hands (drawn from a standard deck) that contain exactly three fives.

The number of ways, in which 3 fives can be picked out of 4 available fives would be 4C3. The number of ways in which 2 non-five cards can be picked out of the 48 available non-five cards would be 48C2.

$4C3=\frac{4!}{3!(4-3)!}=\frac{4*3!}{3!*1}=4$

$48C2=\frac{48!}{2!(48-2)!}=\frac{48*47*46!}{2*1*46!}=24*47=1128$

We can choose exactly three fives from five-card hands in $4C3*48C3$ ways.

$4C3*48C3=4*1128=4512$

Therefore, 4512 five card hands contain exactly three fives.

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3 years ago