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Zarrin [17]
3 years ago
9

Solve each equation 3x+2(5x-3)=7

Mathematics
1 answer:
Sloan [31]3 years ago
7 0

Answer:

1

Step-by-step explanation:

Step 1:

3x + 2 ( 5x - 3 ) = 7

Step 2:

3x + 10x - 6 = 7

Step 3:

13x - 6 = 7

Step 4:

13x = 13

Answer:

x = 1

Hope This Helps :)

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When she subtracts 4 from both sides, Startfraction one-half EndFraction x equals negative StartFraction one-half EndFraction x.
timama [110]

The value of x in the equation 1/2x = -1/2x when 4 is subtracted from both sides is 0(not defined)

Subtraction of fraction

Startfraction one-half EndFraction x equals negative StartFraction one-half EndFraction

1/2x = -1/2x

  • Subtract 4 from both sides

1/2x - 4 = -1/2x - 4

(x-8) / 2 = (-x-8) / 2

(x - 8) / 2 = (-x-8) / 2

  • cross product

2(x - 8) = 2(-x - 8)

2x - 16 = -2x - 16

2x + 2x = -16 + 16

4x = 0

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7 0
2 years ago
B(n)=−1(2) ^n−1<br> What is the 5th term in the sequence?
Rashid [163]

Answer:

8

Step-by-step explanation:

                                  aₙ = 2ⁿ⁻¹

a₅ = 2⁴⁻¹ =2³=8

4 0
3 years ago
A sphere has a volume of 1,436. 03m3, what is the approximate length of its radius?.
makkiz [27]

The sphere with the volume 1436.03 m³ has 7m long radius.

To find out the approximate length of its radius by using the formula to calculate volume of sphere is:

V= 4πr³/3

The value of π is 22/7 or 3.14.

So, V = 4 × 3.14 × r³ / 3

Volume of the sphere is given which is 1436.03 m³.

Thus, r³ = 1436.03×3 / 4×3.14

r = ³√ 4308.09/12.56 = ³√343 = 7 m.

Hence, the radius of the given sphere is 7 m.

The cube root of a number is the factor that we multiply by itself three times to get that number.

For example, the cube root of 27 is 3.

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3 0
2 years ago
Select the two values of x that are roots of this equation.<br> x^2+1=5x <br> *APEX
snow_lady [41]

Answer:

\large\boxed{B.\ x=\dfrac{5+\sqrt{21}}{2},\ C.\ x=\dfrac{5-\sqrt{21}}{2}}

Step-by-step explanation:

\text{Use the quadratic formula:}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\================================\\\\\text{We have}:\\\\x^2+1=5x\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\x^2-5x+1=0\\\\a=1,\ b=-5,\ c=1\\\\b^2-4ac=(-5)^2-4(1)(1)=25-4=21\\\\x=\dfrac{-(-5)\pm\sqrt{21}}{2(1)}=\dfrac{5\pm\sqrt{21}}{2}

6 0
3 years ago
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Answer and I will give you brainiliest <br><br><br><br>MATH​
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Answer:

I think your answer is correct

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4 years ago
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