X+5y=12
5y=12-x
y=(12-x)/5
y=12/5-x/5
The intercept is 12/5
Answer:
The inverse of function
is ![\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}](https://tex.z-dn.net/?f=%5Cmathbf%7Bf%5E%7B-1%7D%20%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D%2B7%7D)
Option A is correct option.
Step-by-step explanation:
For the function
, Find 
For finding inverse of x,
First let:

Now replace x with y and y with x

Now, solve for y
Taking 5th square root on both sides
![\sqrt[5]{x}=\sqrt[5]{(y+7)^5}\\\sqrt[5]{x}=y+7\\=> y+7=\sqrt[5]{x}\\y=\sqrt[5]{x}-7](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%7D%3D%5Csqrt%5B5%5D%7B%28y%2B7%29%5E5%7D%5C%5C%5Csqrt%5B5%5D%7Bx%7D%3Dy%2B7%5C%5C%3D%3E%20y%2B7%3D%5Csqrt%5B5%5D%7Bx%7D%5C%5Cy%3D%5Csqrt%5B5%5D%7Bx%7D-7)
Now, replace y with 
![f^{-1} (x)=\sqrt[5]{x}+7](https://tex.z-dn.net/?f=f%5E%7B-1%7D%20%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D%2B7)
So, the inverse of function
is ![\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}](https://tex.z-dn.net/?f=%5Cmathbf%7Bf%5E%7B-1%7D%20%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D%2B7%7D)
Option A is correct option.
Remember that the radicand (the area under the root sign) must be positive or zero for a radical with an even index (like the square root or fourth root, for example). This is because two numbers squared or to the fourth power, etc. cannot be negative, so there are no real solutions when the radicand is negative. We must restrict the domain of the square-root function.
If the domain has already been restricted to

, we can work backwards to add 11 to both sides. We see that

must be under the radicand, so the answer is
A.
Answer:
Step-by-step explanation:
In ΔBCA and ΔDCA,
BC ≅ CD Given
∠BCA ≅∠DCA Given
AC ≅ AC Reflexive property
ΔBCA ≅ ΔDCA S A S congruent
∵ BA ≅ AD CPCT {Corresponding part of congruent triangle}
Answer:
c
Step-by-step explanation:
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