Perpendicular lines have slopes that are negative reciprocals of one another.
slope intercept form (y = mx + b) of the first equation will help us find the slope of the first line: where m = slope
5x-4y=10
-4y=-5x + 10
y=-5/-4 x + 10/-4
y=5/4 x -2.5
if the slope of this line is 5/4 then the slope of the perpendicular line is -4/5.
Therefore with the given information we can state the equation of the second line in point slope form (y-y,) = m(x-x,)
the coordinates of (5,12) can are substituted for x, and y,
so the answer is
(y-12) = -4/5(x-5)
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If it has no real solutions, that means the graph does not intersect the x axis
since we have ax^2+bx+c=0, the parabola opens either up or down
since the vertex is in the second quadrant (x is negative and y is positive in this reigon) and the graph does not cross the x axis, the parabola must open up
if the value of 'a' is positive, then the parabola opens up
so 'a' must be positive
if it is translated to the 4th quadrant, then the vertex is now below the x axis
it will now have 2 x intercepts because the vertex is in the 4th quadrant and look at a graph of a parabola opening up with vertex in 4th quadrant and seehow many time it crosses the x axis
The answer is x=2
explanation:
2+3=5
8 times 2 is 16, minus 11=5
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Answer:
we start with -8 divided by 2 because of PEMDAS
we now have -4
then we do 4-4+3=3
Step-by-step explanation:
