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Snezhnost [94]
3 years ago
5

Angle a =8x+6 Angle b= 4x+38 Solve for x and find the measure of angle b

Mathematics
1 answer:
Savatey [412]3 years ago
3 0

Answer:

Angle\ b= 70\°

Step-by-step explanation:

<u><em>The correct question is</em></u>

Angle a and angle b are vertical angles

Angle a =8x+6

Angle b= 4x+38

Solve for x and find the measure of angle b

we know that

<u><em>Vertical Angles</em></u> are the angles opposite each other when two lines cross. They are always congruent.

m∠a=m∠b -----> by vertical angles

substitute the given values

(8x+6)\°=(4x+38)\°

solve for x

8x-4x=38-6

4x=32

x=8

<em>Find the measure of angle b</em>

Angle\ b= (4x+38)\°

substitute the value of x

Angle\ b= (4(8)+38)\°

Angle\ b= 70\°

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What divided by 6 equals 7
vivado [14]

Answer:

42

Step-by-step explanation:

You can prove this by taking 42 and dividing it by 6, and you will see that the answer is 7. Tip: For future reference, when you are presented with a problem like "What divided by 6 equals 7?", all you have to do is multiply the two known numbers together.

6 0
3 years ago
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In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is
zheka24 [161]

Answer:

f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

Step-by-step explanation:

Let:

M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y

This is and exact equation, because:

\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}

So, define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)

The solution will be given by:

f(x,y)=C_1

Where C1 is an arbitrary constant

Integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y):

f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}

Substitute into \frac{\partial f(x,y)}{\partial y} =N(x,y)

2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y

Integrate \frac{dg(y)}{dy} with respect to y:

g(y)=\int\ {8y} \, dy =4y^2

Substitute g(y) into f(x,y):

f(x,y)=2x^2+4y^2+2xy

The solution is f(x,y)=C1

f(x,y)=2x^2+4y^2+2xy=C_1

Solving y using quadratic formula:

y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

4 0
4 years ago
Can someone please solve number 2 ! I would literally love you forever !!!!
nadya68 [22]

Answer:

sorry i wish i knew how but i would like to give you aomething other than an answer for your question and i hope this is ok.

Step-by-step explanation:

every day is a new day and a new opportunity to change the world no matter how BIG or how small.  even if you make mistakes. always remember this though. whatever you put into the world, whether it be good or bad, it will always come back three times.

meaning that when you do something good something three times as good will happen to you. The same is so for bad except it would be 3 times as bad as will happen to you.   I hope your day is great and may you do many great things.

8 0
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Write the equation of the circle that has a center of (-7, 17) with<br> a radius of V19.
kipiarov [429]

I think your question seems to be :-

Write the equation of the circle that has a center of (-7, 17) with a radius of √19

So , as we know that the equation of circle with centre at <em>(h,k)</em> and <em>radius r</em> is given by {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} . Now , using same concept in this question ;

{:\implies \quad \sf \{x-(-7)\}^{2}+(y-17)^{2}=(\sqrt{19})^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+7)^{2}+(y-17)^{2}=19}}}

<em>This is the required equation of Circle </em>

8 0
2 years ago
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melamori03 [73]
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3 0
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