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JulijaS [17]
3 years ago
12

Convert 66 months to years.

Mathematics
2 answers:
damaskus [11]3 years ago
8 0
It will be 5 years and 5 months.
TiliK225 [7]3 years ago
7 0
66 / 12 = 5.5, thus 5 and a half year or 5 year 6 months
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part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.​
andreev551 [17]

Answer:  \bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}

<u>Step-by-Step Explanation:</u>

Pythagorean Theorem is: a² + b² = c²  , <em>where "c" is the hypotenuse</em>

5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}

Note: (15)² + (3√11)² = hypotenuse²   →   hypotenuse = 18

6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}

Note: 8² + 15² = hypotenuse²   →   hypotenuse = 17

7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}

Note: hypotenuse not needed for tan

8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}

Note: 2² + 6² = hypotenuse²   →   hypotenuse = 2√10

8 0
3 years ago
What are the zeros of the function f(x)= 2x^2-4x-6
jolli1 [7]
The root are x=3 and x=-1

youre welcome :)
5 0
3 years ago
(-1,-8) what is the equivalent number
Keith_Richards [23]

Answer:

8 x n =3647 = 8.1

Step-by-step explanation:

3 0
3 years ago
Tina placed a 15 meter rope along one side of the bicycle path. She hung a ribbon on each end of the rope and every 3 meters in-
dusya [7]
Hello!

She placed 6 ribbons

2 at the ends and 5 every 3 meters
7 0
3 years ago
Triangle ptg has side lengths of 18 27 cm and 13 cm what type of triangle is it
diamong [38]
Angle PTG = arccos((18^2 + 13^2 - 27^2) / (2 x 18 x 13)) = arccos(-236 / 468) = arccos(-0.5043) = 120 degrees.

The triangle is an obtuse triangle (because one of the angles is greater than 90 degrees) and a scalene triangle (because all the sides are not equal).
6 0
3 years ago
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