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Helga [31]
3 years ago
12

What are the first 3 common multiples of 3 and 5

Mathematics
2 answers:
marshall27 [118]3 years ago
5 0
<span>The least common multiple is the smallest number that is divisible by each of the numbers being considered. Example: While 15, 30, 45, 60, 75, ... are all commonmultiplies of 3 and 5, 15 is the smallest number divisible by both 3 and 5. It is the leastcommon multiple.</span>
lianna [129]3 years ago
5 0
3,9,12 for 3 and 5,10,15 for 5 hope you get it next time
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A giant panda lives in the Washington, DC zoo. Another panda weighs 90 kilograms and is 110 months old. List the point that corr
Fofino [41]

Answer:

The point represents a 36 months old Panda whose weight is 82kg

Step-by-step explanation:

Given

See attachment for plane

Required

What does the point shown represent

The point is: (36,82)

Age is plotted on the x-axis and weight on the y-axis:

This means that:

Age= 36\ months

Weight = 82\ kg

<em>So, the point represents a 36 months old Panda whose weight is 82kg</em>

6 0
2 years ago
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One winter morning the temperature was -2 C. By 11:00 am the temperature hd decreased by 3 degrees. At 4:00 pm reached 0 degrees
Temka [501]

Answer:

The temperature rose by 5 degrees celcius between 11 am and 4 pm

Step-by-step explanation:

Here in this question, we want to find the integer which represents the temperature change from 11 am to 4 pm.

Initially, in the morning, the temperature was -2 . By 11, it had decreased by 3 degrees. What this means is that the temperature went down further by 3 degrees.

Mathematically, the temperature at 11 will be -2-3 = -5 degrees celcius

Now at 4 pm, the temperature went from -5 to 0 degrees.

The temperature change between 11 am and 4 pm will be; 0-(-5) = 0 + 5 = 5 degrees celcius

This means that the temperature rose by 5 degrees celcius between 11 am and 4 pm

7 0
3 years ago
Which equation could represent the graph shown below?
almond37 [142]

Answer:

y=-\sqrt{x-2}

Step-by-step explanation:

I used an online graphing calculator and process of elimination...

3 0
3 years ago
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A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee
katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

^nC_r=\dfrac{n!}{(n-r)!r!}

Given : Total multiple-choice questions  = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= ^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84

No. of ways to answer 4 open-ended problems

= ^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= 84\times15=1260

Hence, the correct answer is option A) 1260

5 0
3 years ago
PLEASE HELP WITH MATH PROBLEM 35 POINTS
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