Question

What is the standard form of the equation of the circle in the graph

Answer 1

The standard form of the equation of a circle with center (h, k) and radius r is
   (x-h)² + (y-k)² = r²

You have a circle centered at (-3, 1) with radius 1, so the standard form equation is
   (x+3)² + (y-1)² = 1

Answer 2

Answer:

The standard equation of the circle is $(x+3)^2+(y-1)^2=1^2$.

Step-by-step explanation:

The standard equation of a circle is

$(x-h)^2+(y-k)^2=r^2$

where, (h,k) is center of the circle and r is the radius.

From the given graph is clear that the center of the circle is (-3,1) and radius is 1 unit. So, the standard equation of the circle is

$(x-(-3))^2+(y-1)^2=1^2$

$(x+3)^2+(y-1)^2=1^2$

Therefore the standard equation of the circle is $(x+3)^2+(y-1)^2=1^2$.