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bixtya [17]
3 years ago
6

How to solve it? !! !!

Mathematics
1 answer:
Alex17521 [72]3 years ago
5 0
Am not really sure my answer is right

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12. A scientist is observing a family of mice. There are four nice which are reproducing and doubling in number every month. Whi
Margaret [11]

Answer:

?

x = the number of months pass right

3 0
2 years ago
0.3(3a-4)-0.05(8a)(-7a)
Anit [1.1K]

Answer:

2.8a²+0.9a - 1.2

Step-by-step explanation:

Given the expression 0.3(3a-4)-0.05(8a)(-7a)

Expand using the distributive law

0.3(3a-4)-0.05(8a)(-7a)

0.3(3a)-0.3(4)-0.05(8a)(-7a)

0.9a-1.2 - 0.05(8a)(-7a)

0.9a - 1.2 + 2.8a²

Rearrange

2.8a²+0.9a - 1.2

Hence the required expression is 2.8a²+0.9a - 1.2

3 0
2 years ago
.......................hi I'm board
konstantin123 [22]

Answer:

yes

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A square rug has an area 80ft which is the best approximation of the length of one side of the rug.....Explain...If you can show
kow [346]
So to find the answer, first we need to understand how to approximate square roots. 80 is an imperfect square, so we're going to have to round the answer. To find that, we need to find the multiples 80.

72, 80, 81.
8, x, 9

So the distance apart between 72 and 81 is 9. The answer, x, is obviously between 8 and 9, and since the distance between these to is 9, your answer is going to be 8.9 .
5 0
3 years ago
Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285
Mkey [24]

Answer:

Highway = 155\ miles

City = 130\ miles

Step-by-step explanation:

Given

Highway = 31mi/gallon

City = 26mi/gallon

Total\ Miles = 285

Total\ Gallons = 10

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

c + h = 10 ---- gallons used

and

31h + 26c = 285 --- distance travelled

In the first equation, make c the subject

c = 10 - h

Substitute 10 - h for c in the second equation

31h + 26c = 285

31h + 26(10 - h) = 285

Open bracket

31h + 260 - 26h = 285

Collect like terms

31h - 26h = 285 - 260

5h = 25

Make h the subject

h = \frac{25}{5}

h = 5

Substitute 5 for h in c = 10 - h

c = 10 - 5

c = 5

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

Highway = 31 * 5

Highway = 155\ miles

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

City = 26 * 5

City = 130\ miles

8 0
3 years ago
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