At the district competition for 5th grade jump-roper of the year, the following number of jumps without stopping were recorded p
er student: 203,245,237,233,90,100,100,277,265,264,265,285,288,291, 291,290,300,224,200,257,290,279,266,288 What is the mean number of jumps, rounded to the nearest hundredth? What is the median number of jumps?
We are given with the number of jumps per student. To get the mean, we simply have to add all of them and divide by the number of students mean number of jumps = <span>203 + 245 + 237 + 233 + 90 + 100 + 100 + 277 + 265 + 264 + 265 + 285 + 288 + 291 + 291 + 290 + 300 + 224 + 200 + 257 + 290 + 279 + 266 + 288) / 24 To get th median, arrange the data from lowest to highest and determine the middle value.</span>
From the first picture, the triangle can be redrawn. It is an isosceles triangle. The base angles of an isosceles triangle are angle. Hence, angle A = angle C = 56°.
Note that: angle À + angle B + angle C = 180° (sum of angles in a triangle) 56 + B + 56 = 180° B + 112° = 180° B = 180° - 112° B = 68°