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LenKa [72]
3 years ago
14

The Occupational Outlook Handbook is published by the Bureau of Labor Statistics.

Computers and Technology
1 answer:
nika2105 [10]3 years ago
7 0
HEY THEIR

The correct answer is A. true.

It was written in 1948 by the bureau of Labor statistics .

HOPE IT HELPS YOU
You might be interested in
The Zootopia Police Department is recruiting new officers and has come up with an innovative equation to hire. They define hireS
Dahasolnce [82]

Answer:

#include<iostream>

#include<limits>

#include<iomanip>

using namespace std;

//function that returns true

//if there is invalid input like giving string as input

// for integer value.

bool isInvalidInput()

{

  //return true if cin.fail

  if(cin.fail())

  {

      //clear the buffer

      cin.clear();

      cin.ignore(numeric_limits<streamsize>::max(),'\n');

      return true;

  }

  return false;

}

//function that calculates the hire score for given 3 parameters.

double calHireScore(double agility,double strength,double speed)

{

  return (1.8*agility) + (2.16 * strength) + (3.24 * speed);

}

//calculate hire score for fox.

void calFoxHireScore()

{

  double agility,strength;

 

  cout<<"Enter Agility Value: ";

  //get agility as input and validate it.

  cin >> agility;

  if(isInvalidInput() || agility <= 0)

  {

      cout<<"\nError: Agility value must be > 0"<<endl;

      return;

  }

 

  cout<<"Enter Strength Value: ";

  cin >> strength;

  if(isInvalidInput() || strength <= 0)

  {

      cout<<"\nError: Strength value must be > 0"<<endl;

      return;

  }

 

  cout<<"\nHire Score for Fox: "<<calHireScore(agility,strength,0)<<endl;

}

//function that asks input from user for

//calculating hire score for Sloth.

void calSlothHireScore()

{

  double strength,speed;

 

  cout<<"Enter Strength Value: ";

  cin >> strength;

  if(isInvalidInput() || strength <= 0)

  {

      cout<<"\nError: Strength value must be > 0"<<endl;

      return;

  }

 

  cout<<"Enter Speed Value: ";

  cin >> speed;

  if(isInvalidInput() || speed <= 0)

  {

      cout<<"\nError: Speed value must be > 0"<<endl;

      return;

  }

 

  cout<<"\nHire Score for Sloth: "<<calHireScore(0,strength,speed)<<endl;

}

//function that asks input from user for

//calculating hire score for Bunny.

void calBunnyHireScore()

{

  double agility,speed;

 

  cout<<"Enter Agility Value: ";

  cin >> agility;

  if(isInvalidInput() || agility <= 0)

  {

      cout<<"\nError: Agility value must be > 0"<<endl;

      return;

  }

 

  cout<<"Enter Speed Value: ";

  cin >> speed;

  if(isInvalidInput() || speed <= 0)

  {

      cout<<"\nError: Speed value must be > 0"<<endl;

      return;

  }

 

  cout<<"\nHire Score for Bunny: "<<calHireScore(agility,0,speed)<<endl;

}

//function to display menu for user.

void menu()

{

  cout<<"\n1. Fox"<<endl;

  cout<<"2. Bunny"<<endl;

  cout<<"3. Sloth"<<endl;

  cout<<"0. Quit"<<endl;

  cout<<"Enter your choice: ";

}

//main method

int main()

{

  int choice;

  do

  {

      //asks choice

      menu();

      cin >> choice;

      //if invalid input print erro message

      if(isInvalidInput())

      {

          cout<<"\nError: Invalid choice enetered. Try Again\n";

      }

      else

      {

          cout<<"\n";

          //if any one of the choices do accordingly

          //for invalid choice print error mesage.

          switch(choice)

          {

              case 1:

                  calFoxHireScore();

                  break;

              case 2:

                  calBunnyHireScore();

                  break;

              case 3:

                  calSlothHireScore();

                  break;

              case 0:

                  cout<<"\nQutting...\n";

                  break;

              default:

                  cout<<"Invalid choice entered."<<endl;

                  break;

          }

      }

     

  }while(choice != 0);

 

  return 0;

}

Explanation:

3 0
4 years ago
Write a short paragraph explaining why cross-training employees is imperative.
harina [27]
<span>One of the main deterrents to cross-training is how employees feel about retaining knowledge. An employee may feel their job is threatened if someone else is being trained in their function. It's important that you lay these woes to rest and explain why you are cross-training your employees.</span>
4 0
4 years ago
What are two reasons for using layered protocols? what is one possible disadvantage of using layered protocols?
Ostrovityanka [42]
Some of the disadvantages of using layered protocols are the redundancy and overall lower performance.
Reimplementing everything from remote and wired to connectionless and association situated application correspondence, with each ringer and shriek of BGP, MPLS, multicast steering and so on would be a gigantic endeavor and potentially unmanageable in this solid across the board convention. I could envision specialty utilize situations where most extreme execution is imperative most importantly where an exceptionally basic framework might be wanted.
8 0
3 years ago
In this problem, you will write three methods to:
gulaghasi [49]

Answer:

see explaination for program code

Explanation:

program code below:

class Names{

public static String[] makeNames(String[] array1, String[] array2){

if(array1.length == 0) return array2;

if(array2.length == 0) return array1;

String[] res = new String[array1.length*array2.length];

int k = 0;

for(int i=0;i<array1.length;i++){

for(int j=0;j<array2.length;j++){

res[k++] = array1[i] + " " + array2[j];

}

}

return res;

}

public static String[] makeNames(String[] array1, String[] array2, String[] array3){

return makeNames(makeNames(array1, array2), array3);

}

public static void print(String[] array){

for(String name : array){

System.out.println(name);

}

}

public static void main(String[] args) {

String[] first = {"David", "Mike", "Katie", "Lucy"};

String[] middle = {"A","B", "C", "D", "E"};

String[] last = {};

String[] names = makeNames(first, middle, last);

print(names);

print(names);

}

}

8 0
3 years ago
What are the ways of closing an Microsoft word application? ​
Juliette [100K]

Answer:

By pressing key ALT and F4 to close a window application.

Explanation:

<em>Closing Microsoft application comes in different ways such as: </em>

<em> a. Pressing ALT and F4 to close an active window application. </em>

<em>b. Press the X button at the upper right of the screen. </em>

<em> If you are using a MAC or apple computer with Windows emulator, you can simply press on COMMAND key and W key to close an active window application.</em>

4 0
3 years ago
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