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Leokris [45]
2 years ago
9

What should be substituted in a linear equation in order to solve it

Mathematics
2 answers:
Murrr4er [49]2 years ago
8 0

Answer:

A value for x.

Step-by-step explanation:

For example,

y=-3x+6

Substitute a random number for x to find the value of y, after which you'll have a point.

Strike441 [17]2 years ago
6 0

x should be substituted in order to find y

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Help anyone can help me do 16 and 17 question,I will mark brainlest.The no 16 question is find the area of the shaded region​
yanalaym [24]

Answer:

Question 16 = 22

Question 17 = 20 cm²

Step-by-step explanation:

<u>Concepts:</u>

Area of Square = s²

  • s = side

Area of Triangle = bh/2

  • b = base
  • h = height

Diagonals of the square are congruent and bisect each other, which forms a right angle with 90°

Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

<u>Solve:</u>

Question # 16

<em>Step One: Find the total area of two squares</em>

Large square: 5 × 5 = 25

Small square: 2 × 2 = 4

25 + 4 = 29

<em>Step Two: Find the area of the blank triangle</em>

b = 5 + 2 = 7

h = 2

A = bh / 2

A = (7) (2) / 2

A = 14 / 2

A = 7

<em>Step Three: Subtract the area of the blank triangle from the total area</em>

Total area = 29

Area of Square = 7

29 - 7 = 22

-----------------------------------------------------------

Question # 17

<em>Step One: Find the length of PT</em>

Given:

  • PR = 4 cm
  • RT = 6 cm

PT = PR + RT [Segment addition postulate]

PT = (4) + (6)

PT = 10 cm

<em>Step Two: Find the length of S to PT perpendicularly</em>

According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

<em>Step Three: Find the area of ΔPST</em>

b = PT = 10 cm

h = S to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

<em>Step Four: Find the length of Q to PT perpendicularly</em>

Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

<em>Step Five: Find the area of ΔPQT</em>

b = PT = 10 cm

h = Q to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

<em>Step Six: Combine area of two triangles to find the total area</em>

Area of ΔPST = 10 cm²

Area of ΔPQT = 10 cm²

10 + 10 = 20 cm²

Hope this helps!! :)

Please let me know if you have any questions

6 0
2 years ago
Hurry i need help!!
diamong [38]

Answer:

Take rabbit across

go back

Take fox across and go back across with rabbit

take carrots across and leave them with fox

go back and get rabbit

Step-by-step explanation:

4 0
3 years ago
Given that 6 yards is equal to 18 feet, what is the ratio of yards to fee
expeople1 [14]
I'm going to assume you just mean how do you write the ratio, in which case the answers vary
18:6
18 to 6
or
18/6
3 0
3 years ago
Both families use 1250 kWh for the given 30 day period. The Freeman family uses 400 kWh during on-peak hours and 850 during off-
Natalka [10]
Ok ummm I honestly don’t know I’m so sorry I couldn’t help you wit this prob
8 0
3 years ago
A company with n employees publishes an internal calendar, where each day lists the employees having a birthday that day. What i
lutik1710 [3]

Answer: 1-(\frac{364}{365})^n

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_xp^x(1-p)^x, where P(x) is the probability of getting success in x trials, n is the total number of trials and p is the probability of getting success in each trial.

We assume that the total number of days in a particular year are 365.

Then , the probability for each employee to have birthday on a certain day :

p=\dfrac{1}{365}

Given : The number of employee in the company = n

Then, the probability there is at least one day in a year when nobody has a birthday is given by :-

P(x\geq1)=1-P(x

Hence, the probability there is at least one day in a year when nobody has a birthday =1-(\frac{364}{365})^n

5 0
3 years ago
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