Answer:
300 Kilo-meters
Step-by-step explanation:
Since 4 / 5 of a liter runs for 12 kilo-meters and you need to find how much 20 liters would run, you need to find how much a liter can run for.
L is the variable for which how much a liter can run for. Which is what we need to solve.
4 / 5 x L = 12
To isolate L, you need to multiply both sides by 5/4 since multiplying a number by its reciprocal produces one. Note: A reciprocal is a number where the denominator and numerator are switched. Example: 2/3 and 3/2 multiplying it with each other get 6/6 which is 1.
4 / 5 x 5 / 4 x L = 12 x 5 / 4
L = 12 x 5 / 4
L = 60/4
L = 15
Now you know that each liter is worth 15 kilo-meters and you need to find how much 20 liters will run for.
20 x L = Kilo's Ran
20 x 15 = Kilo's Ran
300 = Kilo's Ran
20 Liters will run for 300 Kilo-meters.
I Hope This Helps You :)
4.051 rounded to the nearest hundredth is 4.05 because you rounded down from 1.
Answer:
<h3>⎆ <u>In expanded form :-</u></h3>
# ꧁❣ RainbowSalt2²2² ࿐
The coordinates of point K(7, 0).
Given, JK has midpoint M(7, 2).
And, the coordinates of point J(7, 4).
We have to find the coordinates of point K.
As M is the midpoint, therefore by using the midpoint formula.
(xₙ + yₙ) = (x₁ + x₂/2 , y₁ + y₂/2)
Using x-coordinates,
xₙ = x₁ + x₂/2
7 = x₁ + 7/2
14 = x₁ + 7
or x₁ = 7
Nos using y-coordinates,
yₙ = y₁ + y₂/2
2 = y₁ + 4/2
4 = y₁ + 4
y₁ = 0
Therefore, the coordinates of point K(7, 0).
The coordinates of J(7, 4); K(7, 0); and M(7, 2).
To learn more about midpoints, visit: brainly.com/question/4637646
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