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Veronika [31]
3 years ago
6

Geometry help please. I would like it if you would show work

Mathematics
1 answer:
VashaNatasha [74]3 years ago
5 0

Answer:

AB=sqrt(53)

Step-by-step explanation:

consider the right angle triangle of the top rectangle w sides of 6 n 4

diagonal^2 = 6^2 + 4^2

consider the right angle triangle of the diagonal, AB and 1

AB^2 = diagonal^2 + 1^2

= 6^2 + 4^2 + 1^2

= 36 + 16 + 1

=53

AB=sqrt(53)

ans is a

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