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3 years ago

14

Please help me solve this!!!!!!

1 answer:

anastassius [24]3 years ago

8 0

Answer:

a) reflection across the x-axis, shift 8 units left

b) vertical stretch of 2, reflection across the y-axis, shift up 1

Step-by-step explanation:

The negative sign outside the square root represents a reflection across the x-axis, and the +8 inside represents a shift 8 to the left

The 2 outside the square root represents a vertical stretch of 2, and the negative sign inside the square root represents a reflection across the y-axis. The +1 at the end represents a shift up 1

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Help T-T I’m a bit stuck

ddd [48]

Answer:

It is the 3rd option. If it doesn't have a line below it, the circle should be open. And where the arrow points is where your line should go if that makes sense.

Step-by-step explanation:

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3 years ago

Lamont Gatling purchased a phone answering system for his home office. The list price was $99.86. He also purchased a 12-foot ha

Natali5045456 [20]

Answer:

$130.7086

Step-by-step explanation:

List price of phone answering system = $99.86

Handset cord = $8.95

Telephone wire = 45 cent/foot ; length = 50 feet

Rebate on phone system = $5

Store coupon =$1 of each accessory

Sales tax = 6% on final price

Price before coupon = (99.86 + 8.95 + (50*0.45)) =$131. 31

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Sales tax = 0.06 * $123.31 = $7.3986

Amount paid = $123.31 + $7.3986 = $130.7086

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3 years ago

1-7 blanks plz help its due soon!

Delvig [45]

X-int: (-1+2 square root of 2, 0) & -1-2 square root of 2, 0)

Y-int: (0,-7)
Vertex: (-1,-8)
AOS: x= -1
Max/Min Value: (-1,-8)

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3 years ago

Find all solutions to the equation in the interval [0, 2π). (3 points) cos 4x - cos 2x = 0 0, two pi divided by three. , four pi

salantis [7]

Answer:

$x=0,x=\pi,x=\frac{\pi}{3},x=\frac{2\pi}{3},x=\frac{4\pi}{3},x=\frac{5\pi}{3}$

Step-by-step explanation:

This is a trigonometric equation where we need to use the cosine of the double-angle formula

$cos4x=2cos^22x-1$

Replacing in the equation

$cos4x - cos2x = 0$

We have

$2cos^22x-1 - cos 2x = 0$

Rearranging

$2cos^22x - cos 2x-1 = 0$

A second-degree equation in cos2x. The solutions are:

$cos2x=1,cos2x=-\frac{1}{2}$

For the first solution

cos2x=1 we find two solutions (so x belongs to [0,2\pi))

$2x=0, 2x=2\pi$

Which give us

$x=0,x=\pi$

For the second solution

$cos2x=-\frac{1}{2}$

We find four more solutions

$2x=\frac{2\pi}{3},2x=\frac{4\pi}{3},2x=\frac{8\pi}{3},2x=\frac{10\pi}{3}$

Which give us

$x=\frac{\pi}{3},x=\frac{2\pi}{3},x=\frac{4\pi}{3},x=\frac{5\pi}{3}$

All the solutions lie in the interval $[0,2\pi)$

Summarizing. The six solutions are

$x=0,x=\pi,x=\frac{\pi}{3},x=\frac{2\pi}{3},x=\frac{4\pi}{3},x=\frac{5\pi}{3}$

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Elan Coil [88]

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Step-by-step explanation:

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