Anonymous's answer is completely correct. I thought this problem was asking how to find the distance along the function from the point (2,2^8), and wrote the answer to that nice, tasty problem.
Simply integrate the line element with respect to some affine parameter!
<span><span>L=<span>∫10</span><span><span><span><span>(<span><span>∂x</span><span>∂λ</span></span>)</span>2</span>+<span><span>(<span><span>∂y</span><span>∂λ</span></span>)</span>2</span></span><span>−−−−−−−−−−−−−</span>√</span>dλ</span><span>L=<span>∫01</span><span><span><span>(<span><span>∂x</span><span>∂λ</span></span>)</span>2</span>+<span><span>(<span><span>∂y</span><span>∂λ</span></span>)</span>2</span></span>dλ</span></span>
In this case,
<span><span>x(λ)=λ(X−2)+2,</span><span>x(λ)=λ(X−2)+2,</span></span>
<span><span>y(λ)=(λ(X−2)+2<span>)8</span>.</span><span>y(λ)=(λ(X−2)+2<span>)8</span>.</span></span>
<span>Note that this approach can also solve the original problem, with some simplification.</span>
Hi there! To find the total price for Ray's car, multiply the price of the car by 111% (1.11), because that will take us straight to finding the total price of the car. 16,948 * 111% (1.11) is 18,812.28. There. The total price for Ray's car is $18,812.28.
The answer is x = 17, hope this helps :)
Answer:
<u><em>1st equation:</em></u>
Simplify the numerator
(zero divided by any number (other than zero) is zero)
1st equation is correct
<u><em>2nd equation:</em></u>
This is because a negative number divided by a positive number is a negative number.
So, 
is incorrect.
2nd equation is incorrect
Answer:
The center is at (0,0)
The vertices are at ( (
±2 sqrt(2),0)
foci are (
±sqrt(5),0)
Step-by-step explanation:
3x^2 + 8y^2 = 24
Divide each side by 24
3x^2 /24 + 8y^2/24 = 24/24
x^2/8 + y^2 /3 = 1
The general equation of an ellipse is
(x-h)^2/ a^2 + (y-k)^2 / b^2 = 1
a>b (h,k) is the center
the coordinates of the vertices are (
±a,0)
the coordinates of the foci are (
±c,0), where ^c2=a^2−b^
2
The center is at (0,0)
a = sqrt(8) = 2sqrt(2)
The vertices are at ( (
±2 sqrt(2),0)
c = 8 - 3 =5
foci are (
±sqrt(5),0)
