Question

(PLS HELP?) Quadrilateral WXYZ is a rectangle. The perimeter of triangle XYZ=24, XY+YZ=5x-1, and XZ=13-x. Find the length of WY.

Answer 1

$P_{\Delta XYZ}=24;\ |XY|+|YZ|=5x-1;\ |XZ|=13-x\\\\P_{\Delta XYZ}=|XY|+|YZ|+|XZ|\\\\subtitute\\\\24=(5x-1)+(13-x)\\\\5x-1+13-x=24\\\\4x+12=24\ \ \ |subtract\ 12\ from\ both\ sides\\\\4x=12\ \ \ \ |divide\ both\ sides\ by\ 4\\\\x=3\\\\WXYZ\ is\ a\ rectangle\ therefore\ |WY|=|XZ|\\\\|WY|=13-x\\\\Answer:\boxed{|WY|=13-3=10}$