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soldi70 [24.7K]
3 years ago
13

What is the modulus of 2 – 3i?

Mathematics
1 answer:
CaHeK987 [17]3 years ago
8 0
A modulus is pretty much just the square root of x^2 + y^2, where y is the number that stands with the imaginary “i” and x is the real number. In this case, x is 2 and y is 3, so your modulus would be the square root of 4 + 9 (2^2 + 3^2), or the square root of 13.
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Answer:

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Step-by-step explanation:

The problem states that the box has square ends, so you can express volume with:

v=x^{2} y

Using the restriction stated in the problem to get another equation you can substitute in the one above:

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Substituting <em>y</em> whit this equation gives:

v=x^{2} (84-4x)\\\\v=84x^{2} -4x^{3}

Now find the limit of <em>x</em>:

\frac{84x^{2}-4x^{3}}{dx}=168x-12x^{2}\\\\x=\frac{168}{12}=14

Find the length:

y=84-4(14)=28

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v=(14)^{2}(28)= 5488

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3 years ago
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