Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer: 24
Step-by-step explanation: Multiply 4 by 6 to get 24
C= 5.5 I'm pretty sure that's the answer
d= 4.5 and c+ 5.5
Because 4.5 plus 1.0 = 5.5
since c is one more than d
5.5 plus 4.5 = 10
About 17 times. Just do 69/4
