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4 years ago

The attendance for several baseball games is shown in the table.

Mathematics

2 answers:

san4es73 [151]4 years ago

5 0

Answer:

"The attendance increased by an average of 25 people per game from game 2 to game 5"

Step-by-step explanation:

2nd game had attendance of 680

5th game had attendance of 755

THe increase in number is:

755 - 680 = 75 people

From 2nd to 5th, it is 3 games, so to find PER GAME attendance increase, we divide the increase by number of games. That is:

75/3 = 25

Hence,

<u>"The attendance increased by an average of 25 people per game from game 2 to game 5"</u>

alexdok [17]4 years ago

3 0

Answer:

748 total

Step-by-step explanation:

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4 years ago

Two cards are selected at random without replacement from a well-shuffled deck of 52 playing cards. Find the probability of the

Vlad [161]

<h2>The probability that a pair is not drawn = 0.765</h2>

Step-by-step explanation:

Here, the total number of cards in the given deck = 52

The total number of suits = 4 (13 cards each)

Now, P( Drawing 2 clubs) = $\frac{^{13}C_2}{^{52}C_2} = \frac{78}{1326} = (\frac{1}{17} )$

Similarly, P( Drawing 2 diamond ) = $\frac{^{13}C_2}{^{52}C_2} = \frac{78}{1326} = (\frac{1}{17} )$

P( Drawing 2 spades) = $\frac{^{13}C_2}{^{52}C_2} = \frac{78}{1326} = (\frac{1}{17} )$

P( Drawing 2 hearts ) = $\frac{^{13}C_2}{^{52}C_2} = \frac{78}{1326} = (\frac{1}{17} )$

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= P( Drawing 2 clubs) + P( Drawing 2 diamond ) P( Drawing 2 spades)+ P( Drawing 2 hearts ) = $(\frac{1}{17})+ (\frac{1}{17})+ (\frac{1}{17})+ (\frac{1}{17}) = 4\times (\frac{1}{17}) = \frac{4}{17} = 0.2352$

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The answer is D 28 feet

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4 years ago

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