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olga_2 [115]
2 years ago
12

What is the use of form in HTML​

Computers and Technology
1 answer:
icang [17]2 years ago
5 0

Answer:

to make the internet faster

Explanation:

becuase it will have a faster act on the computer so the computer could process the information for it later to be used

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Convert<br> 0.625 to binary
Anastaziya [24]

\huge{ \rm{Question:}}

Convert

0.625 to binary

\huge{ \rm{Answer:}}

Translate 0.625 into a fraction. We all know that 0.5 is ½. We know that the remainder, 0.125, is ⅛. Add them together, and you get ½ + ⅛ = ⅝.

Now, in binary, the positions to the right of the point are , which is ½, ¼, and ⅛ respectively.

⅝ is 5 × ⅛. 5 in binary is 101. So, ⅝ is

= 0.101

8 0
2 years ago
Units of distance on a computer’s screen are measured in microns.
Trava [24]

Answer:

true

Explanation:

why xzuse

5 0
3 years ago
What two technologies below are hybrid processors that can handle 32 bit and 64 bit operating systems natively?
Vitek1552 [10]
For the answer to the question above asking <span>What two technologies below are hybrid processors that can handle 32 bit and 64 bit operating systems natively?
I believe the answer here is Intel and AMD (Advance Micro Devices)
I hope my answer helped you.</span>
4 0
3 years ago
What are some of the general components of an IDE?
AysviL [449]

Answer:

An IDE normally consists of a source e editor, build automation tools. Most modern IDEs have intelligent code completion. Some IDEs contain a compiler, interpreter, or both.

5 0
3 years ago
Write a computer program that determines how many grades are between 0 and 19.
True [87]

Answer:

public class nnn {

   public static void main(String[] args) {

       int [] examScores = {31, 70, 92, 5, 47, 88, 81, 73, 51, 76, 80, 90, 55, 23, 43,98,36,87,22,61, 19,69,26,82,89,99, 71,59,49,64};

       int zeroTo19 = 0;

       int nineteenTo39 = 0;

       int fortyTo59 = 0;

       int sixtyTo79 = 0;

       int eightyTo100 = 0;

       for(int i =0; i<examScores.length; i++){

           if(examScores[i]<=19){

               zeroTo19++;

           }

           else if(examScores[i]>19&&examScores[i]<=39){

               nineteenTo39++;

           }

           else if(examScores[i]>39&&examScores[i]<=59){

               fortyTo59++;

           }

           else if(examScores[i]>59&&examScores[i]<=79){

               sixtyTo79++;

           }

           else {

               eightyTo100++;

           }

       }

       System.out.println("0 - 19 is "+zeroTo19);

       System.out.println("20 - 39 is "+nineteenTo39);

       System.out.println("40 - 59 is "+fortyTo59);

       System.out.println("60 - 79 is "+sixtyTo79);

       System.out.println("80 - 100 is "+eightyTo100);

   }

}

Explanation:

  • This has been solved with Java
  • Create an array of the exam scores
  • Create new variables for each of the score range
  • Use multiple if statements as u loop through the array to determine the range of scores
  • Finally outside the loop print them variables out
7 0
2 years ago
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