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olga_2 [115]
3 years ago
12

What is the use of form in HTML​

Computers and Technology
1 answer:
icang [17]3 years ago
5 0

Answer:

to make the internet faster

Explanation:

becuase it will have a faster act on the computer so the computer could process the information for it later to be used

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HELP I WILL GIVVE BRAINLY AND 15 POINTS
levacccp [35]

Answer:

Because someone was hittting the space bar in the message instead of typing letters and numbers

Explanation:

Because they were bored or it was a glitch

4 0
3 years ago
What is company NDR?​
lina2011 [118]

Answer:

Explanation:

NDR is a multinational American based company with international branches in Thailand, Cambodia, and Myanmar in the telecom industry and media with sales of over US$100 Million. The company develops application store (APP Store) and application (APP) for mobile devices with 700,000+ apps in the app store.

7 0
3 years ago
What is an 8086 microprocessor used for
Liula [17]
A sixteen bit microprocessor chip used in early IBM PCs. The Intel 8088 was a version with an eight-bit externaldata bus.

The Intel 8086 was based on the design of the Intel 8080 <span>and </span>Intel 8085 (it was source compatible with the 8080)with a similar register set, but was expanded to 16 bits. The Bus Interface Unit fed the instruction stream to theExecution Unit through a 6 byte prefetch queue, so fetch and execution were concurrent - a primitive form ofpipelining (8086 instructions varied from 1 to 4 bytes).

It featured four 16-bit general registers, which could also be accessed as eight 8-bit registers, and four 16-bit indexregisters (including the stack pointer). The data registers were often used implicitly by instructions, complicatingregister allocation for temporary values. It featured 64K 8-bit I/O (or 32K 16 bit) ports and fixed vectored interrupts.There were also four segment registers that could be set from index registers.

The segment registers allowed the CPU to access 1 meg of memory in an odd way. Rather than just supplyingmissing bytes, as most segmented processors, the 8086 actually shifted the segment registers left 4 bits and addedit to the address. As a result, segments overlapped, and it was possible to have two pointers with the same valuepoint to two different memory locations, or two pointers with different values pointing to the same location. Mostpeople consider this a brain damaged design.

Although this was largely acceptable for assembly language, where control of the segments was complete (it couldeven be useful then), in higher level languages it caused constant confusion (e.g. near/far pointers). Even worse, thismade expanding the address space to more than 1 meg difficult. A later version, the Intel 80386, expanded thedesign to 32 bits, and "fixed" the segmentation, but required extra modes (suppressing the new features) forcompatibility, and retains the awkward architecture. In fact, with the right assembler, code written for the 8008 canstill be run on the most <span>recent </span>Intel 486.

The Intel 80386 added new op codes in a kludgy fashion similar to the Zilog Z80 and Zilog Z280. The Intel 486added full pipelines, and clock doubling (like <span>the </span>Zilog Z280).

So why did IBM chose the 8086 series when most of the alternatives were so much better? Apparently IBM's own engineers wanted to use the Motorola 68000, and it was used later in the forgotten IBM Instruments 9000 Laboratory Computer, but IBM already had rights to manufacture the 8086, in exchange for giving Intel the rights to its bubble memory<span> designs.</span> Apparently IBM was using 8086s in the IBM Displaywriter word processor.

Other factors were the 8-bit Intel 8088 version, which could use existing Intel 8085-type components, and allowed the computer to be based on a modified 8085 design. 68000 components were not widely available, though it could useMotorola 6800 components to an <span>extent.
</span>
Hope this helps
7 0
3 years ago
Write a program that reads a list of words. Then, the program outputs those words and their frequencies. Ex: If the input is: he
Tpy6a [65]

Answer:

#Declare variable to get the input

#list from the user

input_list = input()

#split the list into words by space

list = input_list.split()

#Begin for-loop to iterate each word

#to get the word frequency

for word in list:

#get the frequency for each word

frequency=list.count(word)

#print word and frequency

print(word,frequency)

Explanation:

This program that we are told to write will be done by using python programming language/ High-level programming language.

The question wants us to write a program in which the output will be as below;

hey 1

hi 2

Mark 1

hi 2

mark 1

Just by imputing hey hi mark hi mark.

Just copy and run the code below.

#Declare variable to get the input

#list from the user

input_list = input()

#split the list into words by space

list = input_list.split()

#Begin for-loop to iterate each word

#to get the word frequency

for word in list:

#get the frequency for each word

frequency=list.count(word)

#print word and frequency

print(word,frequency)

4 0
3 years ago
Design a program that will receive a valid time in the 24-hour format (e.g. 2305) and convert to its equivalent 12-hour format (
coldgirl [10]

Answer:

import java.io.*;

public class Main

{

  public static void main(String[] args) throws IOException {

      BufferedReader bufferObject=new BufferedReader(new InputStreamReader(System.in));

      String stringObject=bufferObject.readLine();

      while(!stringObject.equals("99:99AM")){

      System.out.println(convertedTime(stringObject));

      stringObject=bufferObject.readLine();

      }

  }

  public static String convertedTime(String stringObject){

  String s=stringObject.substring(stringObject.length()-2);

  String[] timeObject=stringObject.substring(0,5).split(":");

  if(s.equals("AM")){

  if(timeObject[0].equals("12")) return "00"+timeObject[1];

  else return timeObject[0]+timeObject[1];

  }

  else{

  if(timeObject[0].equals("12")) return "12"+timeObject[1];

  else{

  int hours=Integer.valueOf(timeObject[0]);

  timeObject[0]=String.valueOf(12+hours);

  return timeObject[0]+timeObject[1];

  }

  }

 

  }

}

Explanation:

  • Inside the main method run a while loop until stringObject is not equal to the string "99:99AM".
  • Call the convertedTime method and display the results.
  • Use the same hours and minutes except for 12th hour If the time is in AM.
  • Use "00" instead of 12, if it is 12th hour.
  • Add hours to 12, if the time is in PM and don't change anything in case of 12.
8 0
3 years ago
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