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3 years ago

How much will $600 amount to be if it is invested at 10% interest compounded semiannually (two times a year) for 4 years?

Mathematics

1 answer:

Orlov [11]3 years ago

7 0

=600(1+0.1/2)^8 Use the calculator to get the answer :-)

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Dan's ice cream comes on cartons of two sizes. the large carton holds 4 1/2 pounds. the small carton holds 1 3/4 pounds less. ho

KIM [24]

2 3/4
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You just subtract them. :)

6 0

3 years ago

What’s the answer to 7^3x=54

HACTEHA [7]

Answer:

x = 54/343

Step-by-step explanation:

$7^3x=54\\\rightarrow 7^3 = 343\rightarrow \text {Solve Exponents} \\343x=54\\\frac{343x}{343} =\frac{54}{343}\\x =\frac{54}{343}$

5 0

3 years ago

5lb 7oz -11oz need help quick

Aliun [14]

Answer:

76 ounces

Step-by-step explanation:

I'm assuming you meant:

5lb+7oz-11oz=

16 ounces in a pound

5lb+7oz-11oz=

80+7-11=

87-11=

76 ounces

3 0

3 years ago

Let us have four distinct collinear points $a,$ $b,$ $c,$ and $d$ on the cartesian plane. the point $c$ is such that $\dfrac{ab}

Deffense [45]

Start with a line segment connecting two points, A and B. $\dfrac{DA}{BA}=3$ means DA is 3 times longer than BA. Clearly, D cannot fall between A and B because that would mean DA is shorter than BA. So there are two possible locations where D can be placed on the line relative to A and B.

But with $\dfrac{DB}{BA}=2$ , or the fact that DB is 2 times longer than BA, we can rule out one of these positions; referring to the attachment, if we place D to the left of A, then DB would be 4 times longer than BA.

Finally, $\dfrac{AB}{CB}=\dfrac12$ , so that CB is 2 times longer than AB. Again we have two possible locations for point C (it cannot fall between A and B), but one of them forces C to occupy the same point as D. However, A, B, C, D are distinct, so C must fall to the left of A.

Now let $d$ be the length of AB. Then the length of CD in terms of $d$ is $4d$ . We have the coordinates of C and D, and the distance between them is $\sqrt{(4-0)^2+(0-4)^2}=4\sqrt2$ . So

$4d=4\sqrt2\implies d=\sqrt2$

The slope of the line through C and D is

$\dfrac{0-4}{4-0}=-1$

and so the equation of the line through these points is

$y-4=-(x-0)\implies x+y=4$

So the coordinates of A are $(x,y)=(x,4-x)$ . The distance between C and A is $d=\sqrt2$ , so we have

$\sqrt{(x-0)^2+(4-x-4)^2}=\sqrt{2x^2}=|x|\sqrt2=\sqrt2\implies|x|=1$

Since A falls to the right of C (in the $x,y$ plane, not just in the sketch), we know to take the positive value $x=1$ . Then the $y$ coordinate is $y=4-1=3$ .