Answer:
7x+6 = 5(x+6)
Step-by-step explanation:
x represents Harry's age now, so 7x represents Nick's age now. (Nick is 7 times as old as Harry.)
In 6 years, Harry's age will be x+6.
In 6 years, Nick's age will be 7x+6, which is 5 times Harry's age at that time, 5(x+6). Hence an appropriate equation is ...
... 7x+6 = 5(x+6)
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Please note that finding the value of x does not give the answer to the question. We are asked for Harry's age in 6 years, so the answer is x+6 (=18).
is is 169.47058823 yes this the anser
<em>Independent variables are variables of a quantity that are not affected by any conditions. </em>
<em>Dependent variables are variables of a quantity that change if conditions relative to that variable changes.</em>
For example, we generally we take x as independent variable by x variable and dependent variable by y variable.
To find the rate of change we get two values of independent variable (x's) and two values of dependent variables (y's) to get two coordinates in form of
(x,1,y1) and (x2,y2).
<h3>And we can find the rate of change by applying slope formula</h3>
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Answer:
After 11 weeks, Darnell′s savings account will have a total of $8,360.
Step-by-step explanation:
The data provided is as follows:
n: 1 2 3 4
f (n): 260 360 460 560
Consider the data for f (n).
The series f (n) follows an arithmetic sequence with a common difference of 100 and first term as 260.
The nth term of an arithmetic sequence is:
![a_{n}=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=a_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Compute the value of f (11) as follows:
![f(11)=\frac{11}{2}[(2\times260)+(11-1)\times 100]](https://tex.z-dn.net/?f=f%2811%29%3D%5Cfrac%7B11%7D%7B2%7D%5B%282%5Ctimes260%29%2B%2811-1%29%5Ctimes%20100%5D)
![=5.5\times[520+1000]\\\\=5.5\times 1520\\\\=8360](https://tex.z-dn.net/?f=%3D5.5%5Ctimes%5B520%2B1000%5D%5C%5C%5C%5C%3D5.5%5Ctimes%201520%5C%5C%5C%5C%3D8360)
Thus, after 11 weeks, Darnell′s savings account will have a total of $8,360.
33% because 66/200 is .33, and convert that to percentage by multiplying by 100