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3 years ago

Mr. Tan's rectangular swimming pool has an area of (81x2 - 144y2) square feet. What are the dimensions of his pool?

Mathematics

2 answers:

Maurinko [17]3 years ago

8 0

Answer:

The pool dimensions are thus (9x - 12y)(9x + 12y)

Step-by-step explanation:

(81x^2 - 144y^2) is the difference of two squares. Note that you must indicate exponentiation with " ^ ."

Factoring the difference of two squares: a^2 - b^2 = (a - b)(a + b)

Thus, (81x^2 - 144y^2) =

The pool dimensions are thus (9x - 12y)(9x + 12y)

Yakvenalex [24]3 years ago

5 0

Answer:

(9x +12y) & (9x - 12y)

Step-by-step explanation:

$(81 {x}^{2} - 144 {y}^{2} ) \\ \\ =(9x)^{2} - {(12y)}^{2} \\ \\ = (9x + 12y)(9x - 12y) \\$

Hence, dimensions of the pool are (9x + 12y) & (9x - 12y)

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3 years ago

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Dmitriy789 [7]

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2 years ago

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tiny-mole [99]

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