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cestrela7 [59]
4 years ago
11

Drag the correct labels to the pie chart. Not all tiles will be used.

Biology
2 answers:
Juliette [100K]4 years ago
6 0

Answer:

Top is trace gasses,

Blue is nitrogen

Red is oxygen

Explanation:

PLATO test

mezya [45]4 years ago
3 0

Explanation:

As shown in the illustration the highest percentage of air is composed of nitrogen gas at 78%. The second highest percentage is oxygen at 21%. The other trace gases, including carbon dioxide, make up about 1% of the gas composition.

Learn More:

For more on air composition check out;

brainly.com/question/10343608

brainly.com/question/14322147

#LearnWithBrainly

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7 0
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What does NBT stand for​
MAXImum [283]

Answer:

Nitroblue tetrazolium (NBT) staining for assessing intracellular reactive oxygen species (ROS) in oocytes and cumulus cells Hope this helps (=^-^=)

5 0
3 years ago
Ting submissions until Wednesday, October 23, 2019 at 2:50 pm
Mama L [17]

Answer:

<u>vacuole</u>

Explanation:

Vacuoles are filled with cell sap which contains sugar, salts and waste products and enclosed by tonoplast, a membrane. They mostly act as a store for sugars and salts, they maintain the shape of the cell and play a role in osmoregulation. They are found in both plant and animal cells.

7 0
4 years ago
1. Walking through the forest, you find a large population of toadstools. From your extensive knowledge of the kingdom fungi, yo
Lena [83]

Answer:

No, observed and expected frequencies are different.

Observed frequencies: p2 = 0.56 , 2pq = 0.375, q2 = 0.062

Expected frequencies: p2 = 0.774 , 2pq = 0.211, q2 = 0.014

Explanation:

Given frequency of recessive genotype (q2)= 14/ 1006 = 0.0139

Frequency of recessive allele s (q) = square root of 0.0139 = 0.12

Frequency of dominant allele S (p) = 1-q = 1-0.12 = 0.88

Expected frequency of homozygous recessive genotype = 0.12 x 0.12 = 0.014

Expected frequency of homozygous dominant genotype = 0.88 x 0.88 = 0.774

Expected frequency of heterozygous dominant genotype = 2pq = 2 x 0.88 x 0.12 = 0.211

Observed frequencies in population 2

Observed frequency of homozygous dominant genotype = 308 / 549 =0.56

Observed frequency of heterozygous dominant genotype = 206 / 549 =0.375

Observed frequency of homozygous recessive genotype = 34 / 549 =0.062

Observed frequencies do not match with expected frequencies.

6 0
4 years ago
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