let's firstly convert the mixed fractions to improper fractions and then add up all four days.
![\bf \stackrel{mixed}{16\frac{3}{4}}\implies \cfrac{16\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{67}{4}}~\hfill \stackrel{mixed}{12\frac{3}{4}}\implies \cfrac{12\cdot 4+3}{4}\implies \cfrac{47}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{all 4 days summed up}}{\cfrac{67}{4}+\cfrac{47}{4}}\implies \cfrac{67+47}{4}\implies \cfrac{114}{4}\implies \cfrac{57}{2}\implies 28\frac{1}{2}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B16%5Cfrac%7B3%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B16%5Ccdot%204%2B3%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B67%7D%7B4%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B12%5Cfrac%7B3%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B12%5Ccdot%204%2B3%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B47%7D%7B4%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Ball%204%20days%20summed%20up%7D%7D%7B%5Ccfrac%7B67%7D%7B4%7D%2B%5Ccfrac%7B47%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B67%2B47%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B114%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B57%7D%7B2%7D%5Cimplies%2028%5Cfrac%7B1%7D%7B2%7D)
Answer:

Step-by-step explanation:
So we have the function:

To find f(-3), substitute -3 for x:

Multiply within the absolute value:

Subtract:

The absolute value of -14 is 14. Thus:

Add:

And we're done!
Hey there!
On this problem, we have to combine like terms. A like term in this sense doesn't have to have the same coefficient, but it has to have the same variable.
Our like terms are 2m and 4m, along with 3 and 5.
When we add 2m and 4m we get 6m, and when we add 5 and 3 we get eight.
Notice how 5 and three are like terms because they're both whole numbers and don't have any variables.
Your solution is 6m + 8.
My advice to you is pay attention to your like terms and don't mix them up. A strategy is to underline like terms in the same color.
Hope this helps!
Answer:
The required value of t is equal to 2
Step-by-step explanation:
We need to solve the following expression :
Now, using the base rule :

Now, using this value of 2

Hence, The required value of t is equal to 2
Answer: The party ended at 11:40