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Bogdan [553]
3 years ago
12

The number of chairs on a ski lift is inversely proportional to the distance between them a lift has 70 chairs when there’s spac

e 24 m apart if 80 evenly spaced chairs are used on the lift how much space will be left between them?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
7 0

Answer:

Space between 80 evenly spaced chairs = 21m

Step-by-step explanation:

So, according to the given statement, we have the following expression:

No. of chairs ∝ \frac{1}{Distance.Between.chairs}

70 chairs are 24m apart, so it can be written as:

70  ∝ \frac{1}{24}

For, 1 chair , we divide both sides by 70

\frac{70}{70} ∝ \frac{1}{24(70)}

1 ∝ \frac{1}{24 (70)}               -----------------------(Equation 1)

<u>For 80 chairs:</u>

Multiply both sides of <em>Equation.1</em> by 80

80  ∝ \frac{80}{24 (70)}      

80  ∝ \frac{1}{21}      

So according to the above relation,

<em>80 evenly spaced chairs will have a space of </em><em>21 m</em><em> between them.</em>

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Three consecutive even numbers have a sum where one half of that sum is between 90 and 105. Write an inequality to find the the
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3 years ago
Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat
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Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

P(t) = 0.8t^{2} + 6t + 19000

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

P(t) = 0.8t^{2} + 6t + 19000

0.8t^{2} + 6t + 19000 = 34200

0.8t^{2} + 6t - 15200 = 0

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

0.8t^{2} + 6t - 15200 = 0

So a = 0.8, b = 6, c = -15200

Then

\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356

t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14

t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

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Janessa can run 1/2 of a mile in 4 1/3 minutes what is her unit rate in miles per minute ​
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Answer:

8 2/3 minutes in 1 mile

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HOPE THIS HELPS

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