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Bogdan [553]
3 years ago
12

The number of chairs on a ski lift is inversely proportional to the distance between them a lift has 70 chairs when there’s spac

e 24 m apart if 80 evenly spaced chairs are used on the lift how much space will be left between them?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
7 0

Answer:

Space between 80 evenly spaced chairs = 21m

Step-by-step explanation:

So, according to the given statement, we have the following expression:

No. of chairs ∝ \frac{1}{Distance.Between.chairs}

70 chairs are 24m apart, so it can be written as:

70  ∝ \frac{1}{24}

For, 1 chair , we divide both sides by 70

\frac{70}{70} ∝ \frac{1}{24(70)}

1 ∝ \frac{1}{24 (70)}               -----------------------(Equation 1)

<u>For 80 chairs:</u>

Multiply both sides of <em>Equation.1</em> by 80

80  ∝ \frac{80}{24 (70)}      

80  ∝ \frac{1}{21}      

So according to the above relation,

<em>80 evenly spaced chairs will have a space of </em><em>21 m</em><em> between them.</em>

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1) The dimension of the rectangle = 85 × 40

2)The area of the rectangle = length × width = 85 × 40  = 3250 square feet.Let x represents the width of the rectangle,

Then According to the question,

The length of the rectangle = 2 x + 5

Also it is given that the perimeter of the rectangle = 250 feet.

But we know that the perimeter of the rectangle = 2 × ( length + width)

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If x = 50,  the perimeter of the rectangle = 6 × 50 + 10 = 310 > 250

Thus, x ≠ 50

If x  = 40, the  the perimeter of the rectangle = 6 × 40 + 10 = 250 = 250

Thus, x = 40

Therefore, the width of the rectangle, x  = 40 feet.

And, the length of the rectangle, 2 x + 5 = 2 × 40 + 5 = 85 feet.

1) The dimension of the rectangle = 85 × 40

2)The area of the rectangle = length × width = 85 × 40  = 3250 square feet.

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