Answer:
22
Step-by-step explanation:
2x -6 = 38
Add 6 to each side
2x-6+6 = 38+6
2x + 44
Divide each side by 2
2x/2 = 44/2
x = 22
Same thing as what you did on the bottom. Find numbers with both 7 as the base and numbers that add to 14 on the top. Possibilities:
1) 7^10•7^4
2)7^6•7^8
37^2•7^12
<em>BD</em> = 56
Step-by-step explanation:
Step 1: In rectangle, the diagonals are congruent and bisect each other.
So, <em>AC</em> = <em>BD</em>
⇒<em>AG</em> + <em>GC</em> = <em>BG</em> + <em>GD</em>
⇒<em>AG</em> + <em>AG</em> = <em>GD</em> + <em>GD</em>
⇒ 2<em>AG</em> = 2<em>GD</em>
⇒<em>AG</em> = <em>GD</em>
⇒ –7<em>j </em>+ 7 = 5<em>j</em> + 43
⇒–7<em>j</em> – 5<em>j</em> = 43 – 7
⇒–12<em>j</em> = 36
⇒<em>j</em> = –3
Step 2: <em>BD</em> = 2<em>DG</em>
<em>BD</em> = 2(5<em>j</em> + 43)
= 2(5 (–3) + 43)
= 2(–15 + 43)
= 2 × 28
= 56
Hence, <em>BD</em> = 56.
Answer:
y = -6
Step-by-step explanation:
12 (5 + 2y) = 4y- (6 - 9y)
= 60 + 24y = 4y - 6 + 9y
= 60 + 24y = 13y - 6
= 24y - 13y = -6 - 60
= 11y = -66
y = -6
30,000
the way you can solve this is by removing all numbers in front of the selected number(in this case, 2 should be removed) then change all numbers behind to 0.
