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m_a_m_a [10]
3 years ago
10

Evaluate: \frac{23}{56} + \frac{3}{8} - ( - \frac{4}{28} )

Mathematics
1 answer:
MrMuchimi3 years ago
5 0
I think this is what you mean. I don't know why the Latex didn't work. Good for you that you can use it.

\frac{23}{56} +  \frac{3}{8} - \frac{-4}{28}
\frac{23}{56} + \frac{3}{8} - \frac{-4}{28} Reduce the 4/28 to 1/7
\frac{23}{56} + \frac{3}{8} - \frac{-1}{7} Make the 2 minuses into a +
\frac{23}{56} + \frac{3}{8} + \frac{1}{7} 56 is the common denominator.
\frac{23}{56} + \frac{21}{56} + \frac{8}{56}

Answer = [23 + 21 + 8] / 56 = 52 / 56 = 13 / 14 When both numerator and denominator are divided by 4

13 / 14 <<<< answer.
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Plsss Help me plsssssssssssss
Mazyrski [523]

Answer:

If, a = 2 and b = 3

<h3>Jada</h3><h3>10a + 1b = 7a + 5b  - 3a + 4b \\ 10(2) + 1(3) = 7(2) + 5(3) - 3(2) + 4(3) \\ 20 + 3 = 14 + 15 - 6 + 12 \\ 23 = 35 \\</h3>

It's not equivalent.

<h3>Diego</h3><h3>4a + 9b = 7a + 5b - 3a + 4b \\ 4(2) + 9(3) = 7(2) + 5(3) - 3(2) + 4(3) \\ 8 + 27 = 14 + 15 - 6 + 12 \\ 35 = 35 \\</h3>

It's equivalent.

The correct equation is 4a + 9b.

5 0
2 years ago
Find expressions for the partial derivatives of the following functions:
nlexa [21]

Answer:

Step-by-step explanation: partial derivative is the differentiation of one variable e.g. X while leaving the values of the other variable e.g. Y

These four questions A, B, C and D have different functions separated by commas. I will not assume the commas to be something else like a plus sign.

A. f(x) = g'(x).k(y) , g'(x) + h(y)

f(y) = k'(y).g(x) , g(x) + h'(y)

B. f(x) = g'x (x+y)

f(y) = g'y (x+y) , h'y (y+z)

f(z) = h'z (y+z)

C. f(x) = f'x (xy) , f'x (zx)

f(y) = f'y (xy) , f'y (yz)

f(z) = f'z (yz) , f'z (zx)

D. f(x) = f'x (x) , g'(x) , h'x (x,y)

f(y) = h'x (x,y)

These are the partial derivative expressions for each variable in each function. You will need to pay a lot of attention to understand:

* while differentiating X alone, functions in Y which are separated by commas from the functions in X, are ignored totally because they are different questions

* In functions where X added to Y is in a bracket e.g. (x+y), to find the derivative of X, Y isn't thrown away because they are joined (by a plus sign) the derivative of X alone in this case would be f'x (x+y)

* f(x), just like g(x), simply means/represents a function in X hence f'(x) means the differentiation of all X-terms in that function

6 0
3 years ago
If you take a number, multiply it by 3, then add 2, you could represent that phrase with the function:
Nutka1998 [239]

Answer: take a number, add 2, and divide it all by 7.

Step-by-step explanation:

Brainliest plz!

7 0
3 years ago
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What is the quotient of 5.846 x 10^7 and 7.9 x 10^2 expressed in scientific notation
serg [7]

Answer:

Da answer issss...7.4 x 10^4..I tink

8 0
3 years ago
What is 15ft by 18ft times 2in depth converted into yards
NeTakaya

Answer:

5 yd³

Step-by-step explanation:

2 in = 1/6 ft

15 ft  ×  18 ft  ×  1/6 ft = 45 ft³

1 ft³ = 9 yd³

45 ft³/9 = 5 yd³

4 0
3 years ago
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