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m_a_m_a [10]
2 years ago
10

Evaluate: \frac{23}{56} + \frac{3}{8} - ( - \frac{4}{28} )

Mathematics
1 answer:
MrMuchimi2 years ago
5 0
I think this is what you mean. I don't know why the Latex didn't work. Good for you that you can use it.

\frac{23}{56} +  \frac{3}{8} - \frac{-4}{28}
\frac{23}{56} + \frac{3}{8} - \frac{-4}{28} Reduce the 4/28 to 1/7
\frac{23}{56} + \frac{3}{8} - \frac{-1}{7} Make the 2 minuses into a +
\frac{23}{56} + \frac{3}{8} + \frac{1}{7} 56 is the common denominator.
\frac{23}{56} + \frac{21}{56} + \frac{8}{56}

Answer = [23 + 21 + 8] / 56 = 52 / 56 = 13 / 14 When both numerator and denominator are divided by 4

13 / 14 <<<< answer.
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Identify the horizontal asymptote of f(x) = quantity 2 x minus 1 over quantity x squared minus 7 x plus 3.
Rina8888 [55]
We must recall that a horizontal asymptote is the value/s of y that the given function approaches to but never reaches. To find this in a rational function, we compare the expressions with highest degree in the numerator and denominator. There are three possible outcome when this happens.

1. if the highest degree (highest exponent) in the numerator is bigger than that of the denominator, then there won't be any horizontal asymptote.

2. if the highest degree in the denominator is bigger, then the horizontal symptote would be y = 0.

3. if they have the same highest degree, then we just get the quotient of their coefficient. 

Now, going back to our function, we have

f(x) = \frac{2x - 1}{x^{2} - 7x + 3}

From this we can see that the highest degree in the numerator is 1 (from 2x) and 2 (from x²) for the denominator. Clearly, it shows that its denominator has a higher degree. And from our discussion, we can conclude that the horizontal asymptote would be y = 0.

Answer: y = 0
3 0
3 years ago
Given the points (6, 6) and (-7, -6) find the slope.
ANEK [815]

Answer:

12/13

Step-by-step explanation:

m=(-6-6)/(-7-6)=-12/-13=12/13

5 0
2 years ago
Solve the following inequality for x, then describe what the graph would look like.
Alex17521 [72]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form:  

x≤−3

Interval Notation: ( − ∞ , − 3 ]

4 0
3 years ago
Help meeeeeeee please :(.
vodomira [7]

Answer:

x^{3} -5x^{2} -6x +8 \frac{-2}{x + 3}

Step-by-step explanation:

            x^{3} -5x^{2} -6x +8 \frac{-2}{x + 3}

x + 3 / x^{4} - 2x^{3}-21x^{2} -10x +22

         -(x^{4} + 3x^{3})

                 -5x^{3} -21x^{2} -10x +22

                 -(-5x^{3} -15x^{2})

                              -6x^{2} -10x +22

                            -(-6x^{2} -18x)

                                            8x +22

                                          -(8x + 24)

                                              \frac{-2}{x + 3}

4 0
3 years ago
(9,5) and (4,-7) find the distance between two points
Pani-rosa [81]

Answer:

13 units

Step-by-step explanation:

Use the distance formula, d = \sqrt{(x2 - x1)^2 + (y2 - y1)^2}, where (x2, y2) and (x1, y1) are two different points on the line.

Plug in the values:

d = \sqrt{(x2 - x1)^2 + (y2 - y1)^2}

d = \sqrt{(9 - 4)^2 + (5 + 7)^2}

d = \sqrt{5^2 + 12^2}

d = \sqrt{25 + 144}

d = \sqrt{169}

d = 13

6 0
3 years ago
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