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kirza4 [7]
3 years ago
10

Solve for a

Mathematics
2 answers:
Ivenika [448]3 years ago
8 0

Answer:

The answer is a = 4.5

Step-by-step explanation:

To find this we start by dividing away the coefficient of a.

10a = 45 ----> Divide both by 10

a = 4.5

I am Lyosha [343]3 years ago
4 0

Answer:

a = 4 1/2

Step-by-step explanation:

10a = 45

Divide each side by 10

10a/10 = 45/10

a = 45/10

Divide the top and bottom by 5

a = 9/2

a = 4 1/2

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16. An employee has to pay 15.5% in taxes. If
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Answer:

379.75

Step-by-step explanation:

15.5 x 2450

100

= 379.75

7 0
3 years ago
1-(1/3) x 1-(1/3) x 1/3
PolarNik [594]

The solution is -4/9x + 1

7 0
3 years ago
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What fraction is the other race?
dolphi86 [110]

Answer:

Solve for x

Step-by-step explanation:

\frac{1}{4} + \frac{1}{12} + \frac{2}{9} + x=1

7 0
3 years ago
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PLEASE HELP!!
beks73 [17]
<span>Let x = the width
:
It says,"The length of a rectangle is 4 less than 3 times the width." write that as:
L = 3x - 4
:
If the perimeter is 40, find the dimensions of the rectangle.
:
We know: 2L + 2W = 40
:
Substitute (3x-4) for L and x for W
2(3x-4) + 2x = 40
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6x - 8 + 2x = 40; Multiplied what's inside the brackets
:
6x + 2x = 40 + 8; do some basic algebra to find x; (added 8 to both sides)

:
8x = 48
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x = 48/8
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x = 6 which is the width
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It said that L = 3x - 4, therefore:
L = 3(6) - 4
L = 18 - 4
L = 14; is the length
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Check our solutions in the perimeter:
2(14) + 2(6) =
28 + 12 = 40</span>
8 0
2 years ago
Read 2 more answers
In a random sample of 8 ​people, the mean commute time to work was 33.5 minutes and the standard deviation was 7.2 minutes. A 95
Elina [12.6K]

Answer: Margin of error = 6.58

Confidence interval =  (26.91, 40.08)

Step-by-step explanation:

Since we have given that

Sample size n = 8

Sample mean = 33.5 minutes

Population standard deviation = 9.5 minutes

At 95% confidence interval,

α = 0.05

t = 1.96

So, Margin of error is given by

t\times \dfrac{\sigma}{\sqrt{n}}\\\\=1.96\times \dfrac{9.5}{\sqrt{8}}\\\\=6.58

Confidence interval would be

Lower limit:

\bar{x}-6.58\\\\=33.5-6.58\\\\=26.91

Upper limit:

\bar{x}+6.58\\\\=33.5+6.58\\\\=40.08

Hence, the interval would be (26.91, 40.08)

But at standard deviation 7.2 minutes, the confidence interval was (27.5, 39.5)

Confidence interval using the standard normal distribution is wider than the confidence interval using t distribution.

3 0
3 years ago
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