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4 years ago

What is 53/200 as a percent.

Mathematics

2 answers:

8090 [49]4 years ago

8 0

The correct answer is:

26.5%.

Explanation:

"Percent" means "per hundred", or "out of 100."

Our fraction is out of 200. To change this to something out of 100, we would divide the numerator and denominator by 2:

$\frac{53}{200} \div \frac{2}{2} \\ \\=\frac{53\div 2}{200\div 2}=\frac{26.5}{100}=26.5 \%$

taurus [48]4 years ago

4 0

$\frac { 53 }{ 200 } \\ \\ =\frac { 26.5 }{ 100 } \cdot \frac { 2 }{ 2 } \\ \\ =\frac { 26.5 }{ 100 } \cdot 1\\ \\ =\frac { 26.5 }{ 100 }$

Therefore your answer is 26.5%.

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2 years ago

Find value of x, show your work

Zina [86]

Here is your answer

$\huge x=\frac{35}{2}cm= 17.5cm$

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4 years ago

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Alex787 [66]

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3 years ago

Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of

IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if n = 100.

(2) A Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable X following a Binomial distribution with parameters n and p.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.10=1$

Thus, a Normal approximation to binomial can be applied for population 1, if n = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided n as follows:

$n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10$

Thus, a Normal approximation to binomial can be applied for population 2, if n = 100, 50, 40 and 20.

8 0

3 years ago

Given that B is between A and C. If AB=x, BC =2x-3, and AC = 30. Find x and bc

Artemon [7]

Answer:

x=11

BC=19

Step-by-step explanation:

AB+AC=AC this is because B is in between A and C. So now we can substitute all of the line segments, so we have

x+2x-3=30 Now you add 2x and x

3x-3=30 Now you add 3 to both sides so you can get 3x alone on one side

3x=33 Now you divide both sides by 3 so you get the x alone on one side

x=11

The next step is to substitute x to find BC.

BC=2x-3 Substitute the x with 11

BC=2(11)-3 Then multiply 2 and 11 because that is the rule with parenthesis

BC=22-3 then subrtact the 3 from 22

BC=19

You can check your work by doing AB+BC=AC

11+19=30 substitute your answers and then add them together

30=30

3 0

3 years ago