1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
krok68 [10]
3 years ago
12

How do i do this equation

Mathematics
1 answer:
Marina86 [1]3 years ago
5 0
X=10. so x-3 would be 7. e would equal 7. so 5x7=35
You might be interested in
A flower show has an inventory of 60 tulips and 100 roses. If T represents tulips and R represents roses, which of the following
PilotLPTM [1.2K]

Answer: 3/5xr=t and 5/3xt=r

Step-by-step explanation:

3 0
3 years ago
The graph shows the cost of renting water skis. Emilia rents skis at noon. What is the fixed cost of renting water skis for any
cluponka [151]
Can you please show the graph
4 0
3 years ago
Micah deposited $4000 between two savings account. One account earns 4%
ludmilkaskok [199]
It is $2000.04 for that one savings account
7 0
3 years ago
Jack bought a pair of pants and a shirt for $56. If the price of a shirt is two-fifth of the price of a pair of pants, then what
Juliette [100K]

Answer:

Fraction: 22 2/5  

Decimal: $22.4

Step-by-step explanation:

2/5 x 56

6 0
3 years ago
Read 2 more answers
Identify the x-intercepts of the function below f(x)=x^2+12x+24
damaskus [11]

<u>ANSWER:  </u>

x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

<u>SOLUTION:</u>

Given, f(x)=x^{2}+12 x+24 -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here, for (1) a = 1, b= 12 and c = 24

X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}

\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}

Hence the x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

8 0
3 years ago
Other questions:
  • Let f (x) = 2x - 1, g(x) = 3x, and h(x) = x2 + 1. Compute the following: h (h(x)) and. g (h (x))
    9·1 answer
  • Please solve 5 problems from Monday and show work.
    9·1 answer
  • Is anyone else Edge not working?
    12·2 answers
  • PLEASE HELP!! 35POINTS!!
    15·1 answer
  • What is the half of 57
    12·2 answers
  • Tyrone is twice as old as his daughter. In six years Tyrone's age will be
    5·1 answer
  • If the following data were linearized using logarithms, what would be the
    13·1 answer
  • Kristan helped her father build an addition to the deck at the back of their house. The addition was 7 feet 11 inches on one sid
    8·1 answer
  • What is 2a + 3x + a + 5x =
    8·1 answer
  • find the measure of angle A using your correct answer from questions 1 2 or 3 A 45 B 36.9 C 53.1 D 35.2​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!