Homework check? if i’m wrong tell me why? :)
1 answer:
You might be interested in
Let <em>x</em> be the number equal to 0.124₅, so that
<em>x</em> = 1•5⁻¹ + 2•5⁻² + 4•5⁻³
Multiply <em>x</em> by 5³ to convert it to a whole number:
5³<em>x</em> = 1•5² + 2•5¹ + 4•5⁰
Convert everything to base 2:
5³ = 125 = 64 + 32 + 16 + 8 + 4 + 1 = 1111101₂
1•5² + 2•5¹ + 4•5⁰ = 25 + 10 + 4 = 39 = 32 + 4 + 1 = 100111₂
Then
1111101₂ <em>x</em> = 100111₂
so that
<em>x</em> = 100111₂ / 1111101₂
I've carried out the first several steps in the division in the attached table, with more bits added to the result. The number in base 2 does not terminate. You end up with approximately
0.010011111101111100111...₂
Answer:
We conclude that the reaction time is increased or remains same by frequent alcohol use.
Step-by-step explanation:
We are given that a substance abuse researcher wants to know whether reaction time is decreased by frequent alcohol use. He randomly selects 164 alcoholics and finds that their mean reaction time (in ms) to a stimulus equals 283.
Reaction times to the stimulus in the general population are distributed normally with a mean equal to 281 and a standard deviation equal to 28.
<u><em>Let </em></u><u><em> = mean reaction time after alcohol use.</em></u>
So, Null Hypothesis, :
281 {means that the reaction time is increased or remains same by frequent alcohol use}
Alternate Hypothesis, :
< 281 {means that the reaction time is decreased by frequent alcohol use}
The test statistics that would be used here <u>One-sample z test statistics</u> as we know about population standard deviation;
T.S. = ~ N(0,1)
where, = sample mean reaction time (in ms) = 283
= population standard deviation = 28
n = sample of alcoholics = 164
So, <u><em>test statistics</em></u> =
= 0.915
The value of z test statistics is 0.915.
<em>Now, at 0.01 significance level the z table gives critical value of -2.3263 for left-tailed test.</em><em> Since our test statistics is more than the critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><em><u>we fail to reject our null hypothesis</u></em><em>.</em>
Therefore, we conclude that the reaction time is increased or remains same by frequent alcohol use.