Ronald’s monthly income = $100,482/12 = $8373.50
Don’t know what the second question is asking
In this situation, choose length and width such that 12.75=l*w. writing it as a mixed number you have 51/4=sqrt51/2*sqrt51/2 or any other combination you can use.
Slope = 2/3
y = mx + b
6 = 2/3(3) + b so b = 4
equation
y = 2/3x + 4
3y = 2x + 12
answer is c.3y = 2x + 12
First isolate the group with h in it
minus 2pir^2 from both sides
s-2pir^2=2pirh
divide both sides by 2pir
(s-2pir^2)/(2pir)=h
What you don't want is the value of r(t) becoming negative. Surely that would represent water escaping the reservoir.
How big can (t) get before water actually starts escaping the reservoir?
Essentially, to figure this out r(t) would have to be equal to 0.
700 - 40t = 0
40t=700
t=700/40=17.5
So the first answer is 17.5 seconds. After this amount of time has elapsed the reservoir will start to lose water as r(t) would become negative.
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The reservoir had the least amount of water in it before it was being filled. That was when t=0. The volume of water in the reservoir wasn't negatively impacted as not enough water had escaped it during the 17.5 to 30 second period.
