Answer:
888.89 km
Step-by-step explanation:
Write the given question as an equation and solve.
80 km = 0.09 × (what distance)
(80 km)/0.09 = what distance . . . . . divide by the coefficient of the variable
888.89 km ≈ what distance
80 km is 9% of 888.89 km
Complete question:
Dr. Lyte wishes to study speed of Reaction Time to press a button in response to the onset of a lamp. The independent variable (V) is the color of the light produced by the lamp (red, orange, yellow, green, or blue) Since only 10 participants are available, she elects to administer the IV within-subjects with all 10 participants being exposed to all five levels of the color variable. The order of the color of the light presentation is to be counterbalanced. Using concepts from the textbook, why would Dr. Lyte need to use counterbalancing in this scenario?
Answer:
Here,
Independent variable (IV) is: the color of the light produced by the lamp (red, orange, yellow, green, or blue)
We are also told only 10 participants are available.
All 10 participants are being exposed to all five levels of the color variable in the same order.
Counterbalancing is said to be a technique used when establishing task order. It helps prevent introduction if cofounding variables.
Dr. Lyte will need to use counterbalancing technique in this scenario because some of the participants may be unable to understand difference in similar colours. Example some participants may not be able to differentiate between orange and red when the red colour comes after orange.
But using counterbalancing technique, Dr. Lyte can avoid such an error.
D cause that’s the answer
To solve this problem, we have to find how long it will take the bullet to travel 5,000 meters. We know that it travels 200 meters per second.
Therefore, if you divide 5,000 meters/200 meters per second, it will give you how many seconds it will take the bullet to travel 5,000 meters.
5,000/200 = 25
Therefore, it will take 25 seconds for the bullet to travel 5,000 meters.
Answer:
400,000,000+30,000,000+200,000+90,000+100
