All categories

4 years ago

What is beta and alpha? I need ASAP

Mathematics

2 answers:

Dmitry [639]4 years ago

8 0

Answer:

see below

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin alpha = opp side/ hyp

sin alpha = 12/ 15

Take the inverse sin of each side

sin^-1 sin alpha = sin^-1 (12/15)

alpha = 53.13010235

sin beta = opp side/ hyp

sin beta = 9 /15

Take the inverse sin of each side

sin^-1 sin beta = sin^-1 (9/15)

beta = 36.86989765

krek1111 [17]4 years ago

4 0

Answer:

alpha: 53.13°

beta: 36.87°

Step-by-step explanation:

sin(theta) = opposite/hypotenuse

sin(alpha) = 12/15 = 0.8

alpha = sin^-1(0.8)

alpha = 53.130102354

beta = 90 - alpha

beta = 90 - 53.1301023542

beta = 36.8698976458

You might be interested in

32-oz container of yogurt for $2.56

LekaFEV [45]

What’s the question?

5 0

3 years ago

Share £15 in 2:3 <br> Please help me put

son4ous [18]

2 ratio 3,so, 2+3=5
15/5=3 add and then division

5 0

4 years ago

Please help me use the photo.

Kobotan [32]

1.E 2.O 3.A 4.D 5.Y 6. N 7.E 8. A 9.O 10.V here's half

3 0

3 years ago

Read 2 more answers

Please need help asap!!

mojhsa [17]

Angle D corresponds to angle Z, so they are congruent.

In a parallelogram, consecutive angles are supplementary.

m<C + m<D = 180

m<C + m<Z = 180

123 + 57 = 180

180 = 180

The statements may be true.

3 0

3 years ago

a carnival game consists of 3 dart throws at a target. The probability of scoring a hit on any one throw is 30%. Using the binom

Ghella [55]

Answer: Probability of scoring 2 hits = 0.63.

Step-by-step explanation:

Since we have given that

Number of dart throws at a target = 3

Probability of scoring a hit on any one throw = 30%

We will use "Binomial Distribution" i.e.

$P=^nC_rp^r(1-p)^{n-r}$

where,

n denotes number of dart throws at a target,

r denotes number of required throws

p denotes probability of success

(1-p) denotes probability of failure

So, Probability of success is given by

$\frac{30}{100}=\frac{3}{10}$

Probability of failure is given by

$1-\frac{30}{100}=\frac{70}{100}=\frac{7}{10}$

We will use "Binomial Distribution" i.e.

$P(X=2)=^3C_2(\frac{3}{10})^2\times (\frac{7}{10})\\\\P(X=2)=\frac{9}{100}\times \frac{7}{100}\\\\P(X=2)=\frac{63}{100}\\\\P(X=2)=0.63$

Hence, Probability of scoring 2 hits = 0.63.

3 0

3 years ago