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3 years ago

11

What is the area of a right triangle with the given vertices?

2 answers:

kap26 [50]3 years ago

7 0

Answer:

a

Step-by-step explanation:

a I gusse (3,1) I not that smart

Bad White [126]3 years ago

3 0

Answer:

i think it is 5 units squared but im not completely sure

Step-by-step explanation:

You might be interested in

What is the equation to (-3,1) and (0,-8)

puteri [66]

The change in x between the two is 3 and the change in y is -9.
Divide -9 by 3 to get -3 using the rise over run slope formula.
The equation is y = -8 + -3x because the -8 in the second set of coordinates is the y-intercept of the equation.
Hope this helps!

4 0

3 years ago

HELP PLEASE!!!! FASTT

Veronika [31]

Answer:

Domain (-3,-2,-1,0,1,2)

Range (-2,0,1,2,3)

This is not a function

Step-by-step explanation:

Domain (-3,-2,-1,0,1,2)

Range (-2,0,1,2,3)

one x-value with two y-values, (-1, 2) and (-1, -2)

not a function

Plotting the graph should be easy

left side are x-values

right side are y-values

4 0

2 years ago

The difference between twice a number, x, and a smaller number, y, is 3. The sum of twice the number and the smaller number is-3

sasho [114]

A. y= 2x - 3 and y= -2x - 3

4 0

3 years ago

Read 2 more answers

Plz give explanation.<br> solve | k-10 | = 3

Ne4ueva [31]

Answer:

13

Step-by-step explanation:

Explanation:

Use the absolute value definition to rewrite the absolute value equation as two separate equations.

k-10=3

k-10=-3

Solve the equation for k

k=13

k-10=-3

k=13

k=7

The equation has 2 solutions, meaning k1=7,k2=13. Which gives you the answer of: 13 (K1=7,k2=13)

6 0

2 years ago

The surface area of a cylinder is increasing at a rate of 9 pi square meters per hour. The height of the cylinder is fixed at 3

Alekssandra [29.7K]

Answer:

$9\pi \text{ cubic meters per hour}$

Step-by-step explanation:

Since, the surface area of a cylinder,

$A= 2\pi r^2 + 2\pi rh$ ................(1)

Where,

r = radius,

h = height,

If $A= 36\pi\text{ square meters}, h = 3\text{ meters}$

$36\pi = 2\pi r^2 + 2\pi r(3)$

$18 = r^2 + 3r$

$\implies r^2 + 3r - 18=0$

$r^2 + 6r - 3r - 18 = 0$ ( by middle term splitting )

$r(r+6)-3(r+6)=0$

$(r-3)(r+6)=0$

By zero product property,

r = 3 or r = - 6 ( not possible )

Thus, radius, r = 3 meters,

Now, differentiating equation (1) with respect to t ( time ),

$\frac{dA}{dt}= 4\pi r\frac{dr}{dt} +2\pi(r\frac{dh}{dt} + h\frac{dr}{dt})$

∵ h = constant, ⇒ dh/dt = 0,

$\frac{dA}{dt} = 4\pi r \frac{dr}{dt} +2\pi h \frac{dr}{dt}$

We have, $\frac{dA}{dt}=9\pi\text{ square meters per hour}, r = h = 3\text{ meters}$

$9\pi = 4\pi (3) \frac{dr}{dt}+2\pi (3)\frac{dr}{dt}$

$9\pi = (12\pi + 6\pi )\frac{dr}{dt}$

$9\pi = 18\pi \frac{dr}{dt}$

$\implies \frac{dr}{dt} =\frac{1}{2}\text{ meter per hour}$

Now,

Volume of a cylinder,

$V=\pi r^2 h$

Differentiating w. r. t. t,

$\frac{dV}{dt}=\pi ( r^2 \frac{dh}{dt}+h(2r)\frac{dr}{dt})=\pi ((3)(6) (\frac{1}{2})) = 9\pi \text{ cubic meters per hour}$

6 0

3 years ago