A network technician is tasked with designing a firewall to improve security for an existing FTP server that is on the company n
1 answer:
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Answer:
a. 1365 ways
b. Probability = 0.4096
c. Probability = 0.5904
Explanation:
Given
PCs = 15
Purchase = 3
Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;
Where
<em>Hence, there are 1365 ways </em>
Solving (b): The probability that exactly 1 will be defective (from the selected 4)
First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)
<em>From the given parameters; 3 out of 15 is detective;</em>
So;
Solving further using binomial;
Where n = 4
For the probability that exactly 1 out of 4 will be defective, we make use of
Substitute 4 for n, 0.2 for p and 0.8 for q
Solving (c): Probability that at least one is defective;
In probability, opposite probability sums to 1;
Hence;
<em>Probability that at least one is defective + Probability that at none is defective = 1</em>
Probability that none is defective is calculated as thus;
Substitute 4 for n and 0.8 for q
Substitute 0.4096 for Probability that at none is defective
Probability that at least one is defective + 0.4096= 1
Collect Like Terms
Probability = 1 - 0.4096
Probability = 0.5904
Answer:
Step by step code along with explanation and output is given below
Explanation:
We can solve this problem using if elif else approach
def main():
# prompts the user to enter an integer from 1 to 10
num = int (input('Enter a number in the range of 1 to 10:\n'))
# using the if elif print out the roman numeral from 1 to 10
if num == 1:
print ('Roman Numeral for 1 is I')
elif num == 2:
print ('Roman Numeral for 2 is II')
elif num == 3:
print ('Roman Numeral for 3 is III')
elif num == 4:
print ('Roman Numeral for 4 is IV')
elif num == 5:
print ('Roman Numeral for 5 is V')
elif num == 6:
print ('Roman Numeral for 6 is VI')
elif num == 7:
print ('Roman Numeral for 7 is VII')
elif num == 8:
print ('Roman Numeral for 8 is VIII')
elif num == 9:
print ('Roman Numeral for 9 is IX')
elif num == 10:
print ('Roman Numeral for 10 is X')
# using the else print out error message whenever user enters any other number not listed above
else:
print ('Error! Wrong Input')
# call the main function
main()
Output:
Enter a number in the range of 1 to 10:
6
Roman Numeral for 6 is VI
Enter a number in the range of 1 to 10:
15
Error! Wrong Input
