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4 years ago

Which represents the compound inequality in interval notation?

2 answers:

6 0

X $\geq$ -3 and x<1
It means is closed bracket to -3 and opened to 1;
x E [-3, 1);

The right answer: <span>C: x E [-3,1)</span>

Viktor [21]4 years ago

3 0

C I think I hope it helps

You might be interested in

List multiples of a given whole number.

ASHA 777 [7]

Answer:

The multiples of a whole number are found by taking the product of any counting number and that whole number. For example, to find the multiples of 3, multiply 3 by 1, 3 by 2, 3 by 3, and so on. To find the multiples of 5, multiply 5 by 1, 5 by 2, 5 by 3, and so on.

Step-by-step explanation:

5 × 1 = 5

5 × 2 = 10

5 × 3 = 15

5 × 4 = 20

2 × 1 = 2

2 × 2 = 4

2 × 3 = 6

2 × 4 = 8

2 × 5 = 10 and so on

4 0

3 years ago

Solve the equation (8÷4-11)p-2p=12.

pickupchik [31]

Answer:

p = -12/11

Step-by-step explanation:

(2-11)p - 2p = 12

-9p - 2p = 12

-11p = 12

p = -12/11

6 0

3 years ago

Read 2 more answers

What's the answer for78.8×55.779

navik [9.2K]

The answer is
4395.3852

4 0

3 years ago

1. How do you define quadratic equations?

oksian1 [2.3K]

Answer:

$ax^{2} +bx+c^{2}=0$

Step-by-step explanation:

A quadratic equation is a equation that takes the form: $ax^{2} +bx+c^{2} = 0$

Ex. Using our definition of quadratic equations, $ax^{2} +bx+c^{2}=0$ ,

We can set a = 2, b = 1, c = 6:

$2x^{2} +x+6^{2}=0$

$2x^{2} +x+36=0$

Which can then be solved (if you are trying to solve it) as:

$(2x+9)(x-8)=0$

$x=\frac{9}{2}, 8$

6 0

3 years ago

write an equation for the line that is perpendicular to the given line and passes through the given point y-3=8/3(x+2);(-2,3)

Stolb23 [73]

Answer:

$y-3=-\frac{3}{8} (x+2)$

Step-by-step explanation:

We can write the equation of a line in 3 different forms including slope intercept, point-slope, and standard depending on the information we have. We have a point (8,1) and a slope from the equation. We will chose point-slope since we have a point and slope.

Point slope: $y-y_1=m(x-x_1)$

$m\neq \frac{8}{3}$ in our new equation because it is perpendicular to it. This means we will need to change it into its negative reciprocal which is $m=-\frac{3}{8}$ .

We will substitute $m=-\frac{3}{8}$ and $x_1=-2\\y_1=3$ .

$y-3=-\frac{3}{8} (x-(-2))$

$y-3=-\frac{3}{8} (x+2)$

This is the equation of the line perpendicular to the equation given that crosses through (-2,3).

4 0

4 years ago