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notka56 [123]
3 years ago
13

If z1 and z2 are 1-i and -2+4i respectively find Im[z1-z2/z1]

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0

Answer:

- 1

Step-by-step explanation:

z₁ - z₂ = 1 - i - (- 2 + 4i) = 1 - i + 2 - 4i = 3 - 5i, thus

\frac{3-5i}{1-i}

Rationalise the denominator by multiplying the numerator/denominator by the complex conjugate of the denominator

The conjugate of 1 - i is 1 + i, so

\frac{(3-5i)(1+i)}{(1-i)(1+i)}

expand numerator / denominator noting i² = - 1

= \frac{3-2i-5i^2}{1-i^2}

= \frac{3-2i+5}{1+1}

= \frac{8-2i}{2}

= 4 - i

Thus Im [\frac{z1-z2}{z1} ] = - 1

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3 years ago
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First, we must use the rule for multiplying fraction. The rule is: a/b times c/d = ac/ bd. Let's substitute our problem into that formation.
\frac{3 \times 7}{4 \times 9}

Second, we can now simplify. (3 times 7 = 21) and (4 times 9 = 36). 
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Third, since our fraction is not in the simplest form, we can simplify it down by listing the factors of both the numerator and denominator and then finding the greatest common factor (GCF). 

Factors of 21: 1, 3, 7, 21
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Fourth, now we can divide our numerator (21) and denominator (36) by our recently found GCF which was 3. 

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Our new fraction in its simplest form is 7/12.

Answer in fraction form: \fbox {7/12}
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7 0
4 years ago
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Can someone help me with this?
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24 is the shaded region of 1 of the triangles.

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The total shaded region is 48 square units.

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Answer:

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