Answer: add 21 to both sides
Step-by-step explanation:
The computation shows that the change in points is 89 3/4 points.
<h3>How to compute the value?</h3>
From the information, at the beginning of the day the stock market goes down 30 3/4 points and stays at this level for most of the day and at the end the stock market goes up 120 1/2 points.
Therefore, the change will be:
= 120 1/2 - 30 3/4
= 89 3/4
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Answer:
84.13% of homes will have a monthly utility bill of more than $135
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
![\mu = 143, \sigma = 8](https://tex.z-dn.net/?f=%5Cmu%20%3D%20143%2C%20%5Csigma%20%3D%208)
What percentage of homes will have a monthly utility bill of more than $135?
We have to find 1 subtracted by the pvalue of Z when X = 135.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{135 - 143}{8}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B135%20-%20143%7D%7B8%7D)
![Z = -1](https://tex.z-dn.net/?f=Z%20%3D%20-1)
has a pvalue of 0.1587
1 - 0.1587 = 0.8413
84.13% of homes will have a monthly utility bill of more than $135
The Answer is 16 I had this
The scale factor is 1/22.
In the drawing, the height of the school shows 1.6 feet.
In order for us to know the actual height, we can have it as.
1.6 = Height of school * (1/22)
1.6 = Height of school / 22
Height of school = 35.2
So the actual height of the school is 35.2 feet.