Answer:
123 full pages
Step-by-step explanation:
Given
Required
Determine the number of full page
To do this, we simply divide the total stamps by stamps in each page;
Then we record only the quotient
The quotient is the digits before the decimal
<em>Hence, she has 123 full pages</em>
Answer:
Step-by-step explanation:
x + y = 7 ------------(I)
y = 7 - x ------------(II)
x + 2y = 11 --------------(III)
Substitute y = 7 - x in equation (III)
x + 2 * (7 -x) = 11
x + 2*7 - 2*x = 11
x + 14 - 2x = 11
x - 2x + 14 = 11
- x + 14 = 11
Subtract 14 from both side
-x = 11 - 14
-x = -3
Multiply both sides by (-1)
x = 3
Substitute x=3 in equation (II)
y = 7 - 3
y = 4
Answer:
we go to the same school
Step-by-step explanation:
kik me at my name
Any answer less than one would work, soothe answers are A and D
Answer:
0.362
Step-by-step explanation:
When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:
- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.
- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14
- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7
- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.
Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability
P = 0.15(3/7) + 0.75(5/14) + (1/12)*(2/7) + (1/60)*(5/14) = 0.362
