Your answer is very close to being correct; however, the true answer is actually

without any parenthesis needed around the fraction. Notice how there is no (x) at the end.
No you can not do get 30 with the sum of 3 odd numbers
Answer: D) 300 degrees (counterclockwise)
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We want to have segment PQ rotate around the center so that it lines up with segment RF. Put another way: we want point P to rotate around the center to have it line up with point R, and we want Q to rotate so that it moves to point F.
Going clockwise, this is a rotation of 60 degrees as the diagram below shows (each blue arc is 30 degrees, so in total it's 30+30 = 60). In that diagram, I'm only focusing on moving point P. Point Q moves in a similar fashion. Since 60 is not an answer, this means 360-60 = 300 must be the answer.
Let x be for unknown number. Let x be first number .
X+1 To be second number .x+2be third number. X+(x+1)+(x+2)=312.
Simplify to get 3x+3=312 . Subtract 3 from both sides 3x-3=312-3. Once you subtract get 3x=109.then divide 3 both sides . 3x/3=309/3. To get x= 103.
Now once you have that First number 103. Second number 103+1=104 . And third number 103+2=105. To check add them 103+104+105=312