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lesya [120]
3 years ago
8

Enter the slope-intercept equation of the line that has slope 12 and y-intercept (0,3).

Mathematics
1 answer:
Nadya [2.5K]3 years ago
4 0

Answer:

y=12x+3

Step-by-step explanation:

The slope-intercept form is y=mx+b. In the equation for slope-intercept form m=slope and b=y-intercept. You have the slope and y-intercept so all you have to do is put them in the right places. Since the slope is 12 your put the 12 where the m is and get y=12x+b. Then since you know the y-intercept is (0,3)=3 then you just need to put the 3 where the b is to get y=12x+3.

Hope this helps!!!

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What is 0.85 as fraction? Show your work please and thank you!
Levart [38]

Answer:

85/100

Step-by-step explanation:

There are only 2 numbers after the decimal point which means that is 0/100. You would get 85/100 and you can't simplify more than that.

Hope This Helps :)

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3 years ago
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Determine if the following relation is a function or not
Darya [45]
1 is not. 2 is. 3 is not. 4 is. 5 is. 6 is. 7 is not. 8 is.
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A
Evgesh-ka [11]
The answer will end up being c
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What’s the answer to this question?
nordsb [41]

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c

Step-by-step explanation:

7 0
3 years ago
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2. Solve the system of equations. Write your answer in parametric vector notation. X, +5x2 + 4x3 + 3x4 +9xs = 18 2x, +6x2 + 4x3
ratelena [41]

Answer:

The system is inconsistent.

Step-by-step explanation:

The system is

x_1+5x_2+4x_3+3x_4+9x_5=18\\2x_1+6x_2+4x_3+6x_4+6x_5=28\\3x_1+7x_2+4x_3+10x_4+x_5=41\\4x_1+6x_2+2x_3+7x_4+4x_5=29

The associated matrix to the system is

\left[\begin{array}{cccccc}1&5&4&3&9&18\\2&6&4&6&6&28\\3&7&4&10&1&41\\4&6&2&7&4&29\end{array}\right]

Now we use row operations to find the echelon form of the matrix:

1. We substract to row 2, two times the row 1.

We substract to row 3, three times the row 1.

We substract to row 4, four times the row 1 and obtain the matrix

\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&-4&-4&0&-12&-8\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]

2. We multiply the second row of the preview step by -1/4. We obtain the matrix

\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]

3.

We add to row 3, eight times the row 2.

We add to row 4, fourtheen times the row 2 and obtain the matrix

\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&-5&10&-155\end{array}\right]

4. We add to row 4 of the preview step, five times the row 3 and obtain the matrix

\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&0&0&-140\end{array}\right]

Using backward substitution we have that

0x_5=-140, then 0=-140 and this is absurd. Then The system is inconsistent.

4 0
4 years ago
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