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3 years ago

13

If AB = 12, and BD = 18 what is the value of BC?

1 answer:

lbvjy [14]3 years ago

7 0

Answer:

6

Step-by-step explanation:

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A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the

iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

$Event\ 1 = \{1,2,3,4,5,6\}$

Next, we list out the sample space of F

$Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\$

$6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12\}$

In (1): the sample space of E is:

$E = \{1\}$

So:

$P(E) = \frac{n(E)}{n(Event\ 1)}$

$P(E) = \frac{1}{6}$

In (2): the sample space of F is:

$F = \{5,5,5,5\}$

So:

$P(F) = \frac{n(F)}{n(Event\ 2)}$

$P(F) =\frac{4}{36}$

$P(F) =\frac{1}{9}$

For E and F to be independent:

$P(E\ and\ F) = P(E) * P(F)$

Substitute values for P(E) and P(F)

This gives:

$P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}$

$P(E\ and\ F) = \frac{1}{54}$

However, the actual value of P(E and F) is 0.

This is so because $E = \{1\}$ and $F = \{5,5,5,5\}$ have 0 common elements:

So:

$P(E\ and\ F) = 0$

Compare $P(E\ and\ F) = \frac{1}{54}$ and $P(E\ and\ F) = 0$ .

These values are not equal.

Hence: the two events are not independent

6 0

3 years ago

2. The path of a high diver is given by y = + (2x2 – 9x – 56), where y is the height of the diver

timofeeve [1]

Answer:

The diver will be 8 feet from the end of the board when he hits the water.

Step-by-step explanation:

The diver hits the water when y = 0.

To find the distance, we have to find the values of x when y = 0.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this problem, we have that:

$y = 2x^{2} - 9x - 56$

$2x^{2} - 9x - 56 = 0$

So

$a = 2, b = -9, c = -56$

Then

$\bigtriangleup = b^{2} - 4ac = (-9)^{2} - 4*2(-56) = 529$

$x_{1} = \frac{-(-9) + \sqrt{529}}{2*2} = 8$

$x_{2} = \frac{-(-9) - \sqrt{529}}{2*2} = -3.5$

It is a horizontal distance, so the answer is a positive value.

The diver will be 8 feet from the end of the board when he hits the water.

7 0

3 years ago

I WILL GIVE BRAINLIEST :)

Triss [41]

Answer: I got 50x+$75 but I’m not too sure for the last step

Step-by-step explanation:

7 0

2 years ago

In the given table we note that there are six clear subintervals: [0, 0.5], [0.5, 1.0], [1.0, 1.5], [1.5, 2.0], [2.0, 2.5], and

gizmo_the_mogwai [7]

Answer:

The width is 0.5.

Δt, can be stated as follows = 0.5

Step-by-step explanation:

The change is 0.5

4 0

2 years ago

Simplify 15(10-4-2)<br> 14<br> 015/2<br> 52-4110<br> O 105-4110

inna [77]

$\qquad\qquad\huge\underline{\boxed{\sf Answer☂}}$

let's simplify ~

$\qquad \sf \dashrightarrow \: \sqrt{5} (10 - 4 \sqrt{2} )$

$\qquad \sf \dashrightarrow \: ( \sqrt{5} \times 10) - ( \sqrt{5} \times 4\sqrt{2)}$

$\qquad \sf \dashrightarrow \: 10 \sqrt{5} - 4\sqrt{10}$

3 0

2 years ago