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Dennis_Churaev [7]
3 years ago
15

What are the dimensions of this matrix?Help!!!

Mathematics
2 answers:
cupoosta [38]3 years ago
4 0

Answer:

The dimensions ⇒ 3 × 4

Step-by-step explanation:

* Any matrix has two dimensions

- Raw and column

- The dimensions very important in the operations on matrices

- We called the number of raw m and the number of column n

- We must write the number of raw before the number of column

- m × n is the dimensions of the matrix

* Example : If the dimension of a matrix is 2 × 3, that

  means the matrix has 2 raw and 3 column

* Now lets look to our problem

∵  It has 3 raw and 4 column

∴ Its dimensions is 3 × 4

marishachu [46]3 years ago
4 0

<u>Answer:</u>

Size of matrix = 3 × 4

<u>Step-by-step explanation:</u>

We are given the following matrix and we are to determine its dimensions:

\left [ \begin {array}{cccc} 1&-3&8&4\\7&5&3&0\\9&6&-2&-1 \end { array } \right ]

We know that the dimension of a matrix is written in the form:

<em>rows × columns</em>

Here we have 3 rows and 4 columns. Therefore, the size of this matrix is 3 × 4.

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Answer:

The area of rhombus PQRS is 120 m.

Step-by-step explanation:

Consider the rhombus PQRS.

All the sides of a rhombus are equal.

Hence, PQ = QR = RS = SP = 13 m

The diagonals PR and QS bisect each other.

Let the point at of intersection of the two diagonals be denoted by <em>X</em>.

Consider the triangle QXR.

QR = 13 m

XR = 12 m

The triangle QXR is a right angled triangle.

Using the Pythagorean theorem compute the length of QX as follows:

QR² = XR² + QX²

QX² = QR² - XR²

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The measure of the two diagonals are:

PR = 2 × XR = 2 × 12 = 24 m

QS = 2 × QX = 2 × 5 = 10 m

The area of a rhombus is:

\text{Area}=\frac{1}{2}\times d_{1}\times d_{2}

Compute the area of rhombus PQRS as follows:

\text{Area}=\frac{1}{2}\times PR\times QS

        =\frac{1}{2}\times 24\times 10\\\\=120

Thus, the area of rhombus PQRS is 120 m.

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