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leonid [27]
4 years ago
9

Francine has $4.35 in dimes and quarters. The number of dimes is five more than the number of quarters. How many of each coin do

es she have?
Mathematics
2 answers:
Leya [2.2K]4 years ago
6 0

344676 I hope that helps

stellarik [79]4 years ago
3 0

Answer:

Franchise has 11 quarters and 16 dimes.

Step-by-step explanation:

Let d represent number of dimes and q represent number of quarters.

We have been given that the number of dimes is five more than the number of quarters. We can represent this information in an equation as:

d=q+5...(1)

We are also told that Francine has $4.35 in dimes and quarters. We can represent this information in an equation as:

0.10d+0.25q=4.35...(2)

Now, we will substitution method to solve linear equations. Upon substituting equation (1) in equation (2), we will get:

0.10(q+5)+0.25q=4.35

0.10q+0.50+0.25q=4.35

0.35q+0.50=4.35

0.35q+0.50-0.50=4.35-0.50

0.35q=3.85

\frac{0.35q}{0.35}=\frac{3.85}{0.35}

q=11

Therefore, Franchise has 11 quarters.

Upon substituting q=11 in equation (1), we will get:

d=11+5

d=16

Therefore, Franchise has 16 dimes.

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(3x + 5y = 7<br> { 4x - y = 5
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Answer:

Step-by-step explanation:

Solution by substitution method

3x+5y=7

and 4x-y=5

Suppose,

3x+5y=7→(1)

and 4x-y=5→(2)

Taking equation (2), we have

4x-y=5

⇒y=4x-5→(3)

Putting y=4x-5 in equation (1), we get

3x+5y=7

⇒3x+5(4x-5)=7

⇒3x+20x-25=7

⇒23x-25=7

⇒23x=7+25

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→(4)

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y=4x-5

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